5/x=25/6 how do I solve it and what is x?

Answers

Answer 1

Answer: First you do 25/6. That is 4 1/6 or 4.1666 recurring. This mean 5 divide by X is 4.1666 recurring. To find X we do 4.16666 divided by 5 so X is 0.8333 recurring.

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The function y = 100(0.5) x
4
models the percent, y, of an initial dose of medicine remaining in a patientbloodstream after x hours.

Based on the model, what percent of the initial amount of medicine will remain in the patient’s bloodstream after 10 hours? Round to the nearest whole percent.

Answers

The percentage of the initial amount of medicine that will remain in the patient’s bloodstream after 10 hours is, 17.7%.

What is a Function?

A function assigns the value of each element of one set to the other specific element of another set.

Since, The function that models the percentage, y, of an initial dose of medicine remaining in a patient's bloodstream after x hours is given as,

⇒ $y = 100 (0.5)^(x/4)$

Now, if we substitute the value of x as 10 because we need to find the percentage of medicine in the body after 10 hours.

Therefore, the value can be written as,

⇒ $y = 100 (0.5)^(x/4)$

Put x = 10;

⇒ $y = 100 (0.5)^(2.5)\n$

⇒ y = 17.677

⇒ y = 17.7

Thus, the percentage of the initial amount of medicine that will remain in the patient’s bloodstream after 10 hours is 17.7%.

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Answer:

18% , 27 Hours

Step-by-step explanation:

On edge 2020

5 pizza cost $60. What will 9 cost

Answers

$540 dollars because 9times 60

Write an equation of the line that is:a) parallel to the line y=4x+1, and that passes through point (2,3)
b) parallel to the line 2y-6x=9, and that passes through point (-2,1)
c) parallel to the line y=4x+3, and that has the same y-intercept as the line y=5x-3
d) parallel to the line -1/2x, and that has the same y-intercept as the line 2y=7x+6
e) perpendiclar to the line 2y-4x=8, and that passes through point (6,-6)
f) perpendicular to the line 2y-5x=15, and has an x-intercept of 3

please help me with all the questions it would mean alot

Answers

$a)\ny=4x+1\na=4\nnew\ y=bx+c\nif\ parallel a=b\ny=4x+c\nsubstituting\point\ (2,3)\n3=4*2+c\nc=-5\ny=4x-5\nb)\n2y-6x=9\n2y=6x+9\ny=3x+4,5\na=3\nnew\ y=bx+c\nif\ parallel a=b\ny=3x+c\nsubstituting\ point\ (-2,1)\n1=4*(-2)+c\nc=9\ny=3x+9\n c)\ny=4x+3\na=4\nnew\ y=bx+c\nif\ parallel a=b\ny=4x+c\nc=-3\ny=4x-3\ne)\n2y-4x=8\n2y=4x+8\ny=2x+4\na= 2 \nnew\y=bx+c\nif\ perpendicular b=-1/a\ny=- (1)/(2) x+c\npoint(6,-6)\n-6=-1/2*6+c\nc=-3\ny=-1/2x-3\nf)\n2y-5x=15\n2y=5x+15\ny=(5)/(2)x+(15)/(2)$