MATHEMATICS HIGH SCHOOL

Solve the equation for y (Y-3)^2=4y-12

Answers

Answer 1
Answer: If you would like to solve the equation for y, you can do this using the following steps:

(y - 3)^2 = 4y - 12
y^2 - 6y + 9 - 4y + 12 = 0
y^2 - 10y + 21 = 0
(y - 7) * (y - 3) = 0
1. y = 7
2. y = 3

The correct result would be y = 7 or y = 3.

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What is the value of x in the equation 4x+8y=40 when y=0.8

Answers

Substitute in 0.8 for y.

4x+8y=40 \n \n 4x + 8(0.8) = 40 \n \n 4x + 6.5 = 40 \n \n 4x = 40 - 6.4 \n \n 4x = 33.6 \n \n x = 8.4 \n \n

The final result is: x = 8.4.

you plug in the y .8 to the8 that is 6.4

them you subtract 40 by 6.4that is  33.6

then you divide that by 4is 8.4

Which is the opposite of -12?

Answers

Answer: The opposite of -12 would be 12. You simply just turn the negative number, into a positive. Hope this helped you.

Step-by-step explanation:

A square has a perimeter of 64 inches What is the length of one side if the square?
What is the area of the square??

Answers

The length of each side is 32

The area is 256
The length is 16

The area is 256

What's the sum of 6 feet 10 inches and 8 feet 9 inches?

Answers

15 feet and 7 inches
reeber 12 inches=1 foot
first add up the feet
6+8=14 feet

add the inches
10+9=19
19in=12in+7in=1ft+7in

add 1 to feet
14+1=15

answer is 15 feet and 7 inches

Describe how to determine the solution of a system of two linear equations by graphing.WEEELPP

Answers

Using the graphing you graph the two equations and then find the point where the two lines of the equation meet.

Hope this helps :)
1). Draw the graph of one equation.

2). On the same graph, draw the graph of the other equation.

3). If the two lines cross, the x and y at the point where they cross are the solution to the system of two equations.

4). If the two lines don't cross, then the system has no solution.

5). If they are the same line, then the two equations are the same equation, and every point on the line is a solution to it.

Enter the equation of the circle described below.

Center (5, 2), radius = 3

Answers

Equation of the circle;
(x-a)^(2) + (y-b)^(2) = r^(2)
a=5, b=2 and r= 3
(x-5)^(2) + (y-2)^(2) = 3^(2)
for a circle with center (h,k) and radius, r
the equaiton is
(x-h)^2+(y-k)^2=r^2

so

center=(5,2), radius=3

(x-5)^2+(y-2)^2=3^2
(x-5)^2+(y-2)^2=9
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