A bag of marbles contains 5 red, 3 blue, 2 green, and 2 yellow marbles.What is the probability that you choose a red marble and then a green marble assuming you replace the first marble?
A)
1
24
B)
5
72
C)
5
66
D)
5
6
Answers
multiple both 10/144
the answer is B 5/72
Related Questions
Which equation is equivalent to the equation 6x + 9=12
For a given input value b, the function g outputs a value a to satisfy the following equation. a-7=3(b+2)a−7=3(b+2)Write a formula for g(b) in terms of b
You plan to buy $12,000 in computers at a local chain store. There are two stores located about the same distance from your office but in different cities with different tax rates. One city has a tax rate of 7% and the other has a tax rate of 8.5%. What percent can you save by going with the lower tax rate? Round your answer to the nearest tenth of a percent, if necessary.
A pelican consumes 33 1/3% of its body weight in one meal. Write this percent as a fraction in simplest form.
Answers
(x-3)(x+9)=-27
x^2+6x-27=-27
add 27 to both sides
x^2+6x=0
factor out x
x(x+6)=0
set each to zero
x=0
x+6=0
x=-6
x=0 and or -6
x=-6 or 0
Answers
(7c)^2 - (5d^3)^2
(7c + 5d^3)(7c - 5d^3)
The answer is: (7c + 5d^3)(7c - 5d^3).
5/21
3/28
4/29
Answers
Answer: The probability that a student chosen at random has a brand X mobile phone given that he has a brand Y mobile phone is 4/29.
Step-by-step explanation:
Since, the total number of students, n(s) = 1,000
The number of students who have X mobile phones, n(X) = 420,
And, number of students who have Y mobile phones, n(Y) = 580,
Thus, the probability of the student that has Y phones,
While, the number of students who have both phones, n(X∩Y) = 80
Thus, the probability of the student who has both phones,
Hence, the probability that a student chosen at random has a brand X mobile phone given that he has a brand Y mobile phone.
Hence, the required probability is 4/29.
Answers
You will start with division
(-12)/3 = -4
and than everything in the [ }
so that means 5 + -4 = 1
-7 + 1
The answer is -6
Answers
31/100
50/100
50 is larger than 31
Therefore 5/10 is larger than 31/100
5/10=50/100
Is 50 bigger than 31? Yes.
5/10>31/100
Answers
The required equation is, y = 40 + 35 x, and the cost for 10 months will be 390.
What is an expression?
Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.
Total charges of gym = Initial service fee + $ 35 per month
Thus, the total charges for 6 months = Initial service fee + 35 × 6 = Initial service fee + 210
According to the question,
Initial service fee + 210 = 250
⇒ Initial service fee = 250 - 210 = $ 40
Hence, the total charges for the gym for x months = 40 + 35x. Here, y represents the total charges for x months,
⇒ y = 40 + 35 x
The total cost of the membership after 10 months will be calculated as:-
y = 40 + 35 x
y = 40 + 35 x 10
y = 390
Therefore, the required equation is, y = 40 + 35 x, and the cost for 10 months will be 390.
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