An airplane over the Pacific Ocean sights an atoll at an 7° angle of depression. If the plane is 663 m above the water, how many kilometers is it from a point 663 m directly above the atoll?(Hint: Make sure your calculator is in degrees!)A. 5399.7 km
B. 5.4 km
C. 81.41 km
D. 760.8 km

Answers

Answer 1

Answer: You need to draw the diagram to understand the problem easily. Teh diagram will show the right triangle, acute angle with the base 7º, height is 663 m, and "x" is the base of the triangle.

using the tangent ratio:

tanΘ = opposite / adjacent

tan7º = 663 m / x

x = 663 m / tan7º
x = 5,399.7 m

change m to km. 1,000 m = 1km

5,399.7m * 1km/1,000 m = 5,399.7 km/1000 = 5.3997 km or 5.4 km

B. 5.4 km

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Compare using <, >, or =.
7 2/5_____ 7 3/8

Answers

7 2/5 as an improper fraction is 37/5 and 7 3/8 as an improper fraction is 59/8. Then we convert those two improper fractions into a decimal (by 100) and get 7 2/5 = 7.4 and 7 3/8 = 7.3, 7.4 is bigger than 7.3 so the answer is...

7 2/5 > 7 3/8

Can someone please actually help me with my math assignments

Answers

what are the assignments?

Help meeeee prettty pleaseee fastttttt

Answers

Answer:

Step-by-step explanation:

Given

y³ = 125 ( take the cube root of both sides )

$\sqrt[3]{y^3}$ = $\sqrt[3]{125}$

y = 5 → D

What is the probability of getting 2 heads up and 1 tails up when flipping three coins?A. 1/6
B. 1/4
C. 3/8
D. 2/3

Answers

Answer: C:3/8

Step-by-step explanation:

Answer: C. 3/8

Step-by-step explanation:

Sorry guys today is not my day :(

Please show your work

Answers

First question...

F = Floor = 3

W = Wall = ?

H = Hypotenuse = 10

-----

3² + W² = 10²

W² = 10² - 3²

W² = 91

W = √91

Answer (3) : √(91) feet [Rounded: 9.54 feet]

---------

Last question...

L² = 112

L = √(112) = √(28)√(4) = √(7)√(4)√(4) = 4√(7)

Answer (4):

4√7 feet

3.
pythagroen theorem
for a right triangl of legs legnth a and b and hypotnuse c
a^2+b^2=c^2
legs are 3 and height
hypotnuse=legnth of lader=10

h^2+3^2=1^2
h^2+9=100
minus 9 both sides
h^2=91
sqr both sides
h=9.539
h=9.54 ft

4.
area=side^2 for a square
112=side^2
sqrt both sides
√112=side
(√16)(√7)=side
4√7 ft=side

3. 9.54 ft
4. 4√7ft

A group of scientist study the effect of chemical on Various strains of bacteria. Strain A started with 6000 cells and decreases at a constant rate of 2000 cells per hour after the chemical was applied. strain B started with 2000 cells and decreased at a constant rate of 1000 cells per hour after the chemical was applied. when will just strains have the same number of cells? explain

Answers

so
number in a=6000-2000x where x=number of hours

number in b=2000-1000x

when will a=b
so set them equal to each other and solve
6000-2000x=2000-1000x
subtract 6000 from both sdies
-2000x=-4000-1000x
add 1000x to both sdies
-1000x=-4000
multiply -1
1000x=4000
divide by 1000
x=4

in 4 hours, they will be the same, but, their numbers will be negative, so there is actually no real life time when they will be the same observe
1 hour: a=4000, b=1000
2 hour a=2000 b=0
3 hour a=0 b=-1000
4 hour a=-2000 b-=-2000
but you can't have -2000 cells, you can only have 0 or more than 0

Final answer:

Strain A and Strain B will have the same number of cells after 2 hours.

Explanation:

To find out when the two strains of bacteria will have the same number of cells, we need to calculate the time it takes for each strain to reach the same cell count. Let's start with Strain A, which decreases at a rate of 2000 cells per hour. We can set up an equation:

6000 - 2000t = 2000

Solving for t, we find that it will take 2 hours for Strain A to reach the same cell count as Strain B. Therefore, the two strains will have the same number of cells after 2 hours.