Answer: a. the elements that make up the compound
Explanation:
Chemical formulas are the symbolic representation of the elements contained in a compound along with their relative proportions.
For example: The chemical formula for water is which shows that it is formed by combination of hydrogen and oxygen in the ratio of 2: 1 respectively.
pH of the solution is determined by litmus paper, pH paper or pH meter.
Boiling point is the temperature at which atmospheric pressure becomes equal to the atmospheric pressure.
B. Athenosphere
C. Hydrosphere
D. Geosphere
(1) Br2(ℓ) (3) KBr(s)
(2) K(s) (4) KBr(aq)
Any type of metal may join with a non-metal, such as carbon, nitrogen, oxygen, sulfur, phosphorus, and selenium, to create ionic compounds.
A chemical compound known as an ionic compound is one that contains ions bound together by the electrostatic forces known as ionic bonding. Despite having both positively and negatively charged ions, or cations and anions, the molecule is generally neutral.
In most cases, ionic compounds are created between metal and nonmetal components. For instance, the ionic compound calcium chloride is made up of the metal calcium (Ca) and the nonmetal chlorine (Cl) (CaCl2).
A nonmetal and a metal can create an ionic bond, which is the attraction between two ions with opposing charges.
Thus, metal are joined with a non-metal, such as carbon, nitrogen, oxygen, sulfur, phosphorus, and selenium, to create ionic compounds.
To learn more about ionic compound, follow the link;
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Answer/Explanation:
Aluminum and oxygen
Fluorine and oxygen
Ionic compounds are formed when any type of metal is combined with a non-metal such as carbon, nitrogen, oxygen, sulfur, phosphorus, and selenium.
(any)metal + nonmetal = ionic compound
is required?
a. 7.00 mL
b. 8.40 mL
c. 17.1 mL
d. 58.3 mL
Answer:
Explanation:
To determine the volume of the stock solution required to prepare 3.50 L of 0.200 M hydro chloric acid, we can use the formula:
M1V1 = M2V2
where:
M1 = concentration of the stock solution
V1 = volume of the stock solution
M2 = desired concentration of the diluted solution
V2 = desired volume of the diluted solution
Let's substitute the given values into the formula:
M1 = 12.0 M
V1 = ?
M2 = 0.200 M
V2 = 3.50 L
Now we can solve for V1:
12.0 M x V1 = 0.200 M x 3.50 L
V1 = (0.200 M x 3.50 L) / 12.0 M
V1 = 0.0583 L
To convert the volume from liters to milliliters, we multiply by 1000:
V1 = 0.0583 L x 1000 mL/L
V1 = 58.3 mL
Therefore, the volume of the stock solution required is 58.3 mL.
So, the correct answer is d. 58.3 mL.
To determine the volume of the stock solution required, we can use the formula:
Molarity1 x Volume1 = Molarity2 x Volume2
Where Molarity1 and Volume1 represent the initial concentration and volume, and Molarity2 and Volume2 represent the final concentration and volume.
Given:
Molarity1 = 12.0 M
Volume1 = ?
Molarity2 = 0.200 M
Volume2 = 3.50 L
Plugging in the values into the formula, we have:
12.0 M x Volume1 = 0.200 M x 3.50 L
Simplifying the equation, we can solve for Volume1:
Volume1 = (0.200 M x 3.50 L) / 12.0 M
Volume1 ≈ 0.0583 L
To convert this to milliliters, we multiply by 1000:
Volume1 ≈ 58.3 mL
Therefore, the volume of the stock solution required is approximately 58.3 mL.
The closest answer option is d. 58.3 mL.
I hope this explanation helps! Let me know if you have any further questions.