Which explains the change in ionization energy that occurs between removing the first and second electrons from an atom?a. The ionization energy decreases because the ratio of the protons to electrons increases.
b. The ionization energy increases because the ratio of the protons to electrons increases.
c. The ionization energy decreases because the ratio of the protons to electrons decreases.d)The ionization energy increases because the ratio of the protons to electrons decreases.

Answers

Answer 1
Answer:

The first and second electrons from an atom can be explained by "the ionization energy decreases because the ratio of the protons to electrons increases."

What is ionization energy?

Ionizations energy, also referred as ionization potential, is the amount of energy necessary to remove an electron from an isolated atom or molecule.

What is electrons?

The electron is just a subatomic particle with a negatively fundamental charged. Consider the nuclear charge of the atom to understand this. The greater the number of protons in the nucleus, the stronger the nucleus's attraction to electrons. This increased affinity makes removing electrons more challenging. The ionization energy reduces within a group as the atom size increases.

The ionization energy falls as the proton-to-electron ratio grows. When electrons are removed from an atom, it becomes more positive, increasing the attraction interactions between protons and neutrons. This makes removing the succeeding electrons more difficult, resulting in a larger ionization energy.

Hence the correct option is a.

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Answer 2
Answer: The change in ionization energy that occurs between removing the first and second electrons from an atom is best described by b. The ionization energy increases because the ratio of the protons to electrons increases. Removing electrons from an atom makes it more positive, making the attractive forces between protons and neutrons stronger. This makes it harder to remove the succeeding electrons, resulting to a higher ionization energy.

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What is the mass/volume percent of a solution with 75g of Na2CO3 dissolved in 20.0 g of water?11%

9.3 %

30%

7.5%

Answers

Answer:

percent by mass = 79%

Explanation:

Data Given:

mass of solute (Na₂CO₃) = 75 g

mass of solvent ( water ) = 20 g

mass percent of solution = ?

Solution:

Formula used to find percent by mass

                          mass of solute / mass of solution x 100 . . . . . . (1)

first we have to find mass of solution

              mass of solution = mass of solute + mass of Solvent . . . . (2)

put values in equation 2

             mass of solution = 75 g + 20 g

             mass of solution = 95 g

Now,

put values in equation 1

 Percent by mass = mass of solute / mass of solution x 100

 Percent by mass = 75 g / 95 g x 100

 Percent by mass = 79 %

so,

The percent of the solution by mass = 79%

***Note:

The same work can be used for the other values too i.e. if you have 20 g of solute and 75 g solvent.

Answer:

The answer is 78.9%

Explanation:

The percentage weight in volume indicates the mass of solute per volume. We will use the% weight/volume formula to calculate what the exercise asks for, as follows:%weight/volume=(solute weight)/(solution volume)x100%= (75 g)/(75+20)= 78.9%

percent Weight/volume=(solute weight)/(solution volume)x100=(75 g)/(75+20)x100=78.9%

During a flame test, ions of a specific metal are heated in the flame of agas burner. A characteristic color of light is emitted by these ions inthe flame when the electrons(1) gain energy as they return to lower energy levels(2) gain energy as they move to higher energy levels(3) emit energy as they return to lower energy levels(4) emit energy as they move to higher energy levels

Answers

The flames being emitted by the ions are as a result of ions 3. emitting  energy as they return to lower energy levels.

When ions are heated:

  • They absorb energy
  • They are able to move around

As they move around, they expend some of that energy and lose it as a result thereby returning to lower energy levels. As that energy is lost, it comes across as light being emitted by the ions.

In conclusion, ions in the flame test emit light as they lose energy and return to a lower energy level.

Find out more at brainly.com/question/6357832.

Answer;

-Emit energy as they return to lower energy levels.

Explanation;

-A characteristic color of light is emitted by these ions in the flame when the electrons emit energy as they return to lower energy levels.

-The metal ions do absorb energy, and the electrons are boosted to higher energy levels, but they emit that energy as they fall to lower levels, and it is the photons of light they are emitting that can be seen.

Ricardo wants to determine the length of a strip of zinc metal. What is the SI unit for length? foot inch liter meter

Answers

Answer : The correct option is, meter

Explanation :

S.I : It is known as the international System of Units. It is defined as a scientific method to express the magnitude of the several basics units.

There are seven basic units in the system from which the other units are derived.

The seven base unit are, meter for length, kilogram for mass, second for time, ampere for current, kelvin for temperature, mole for amount of substance and candela for intensity.

As per question, the S.I unit of length of a strip of zinc metal is, meter.

Hence, the correct option is, meter

The Si unit for length is meters.

Mendeleev’s principle of chemical periodicity states that when the elements are arranged according to their atomic numbers. This periodic law allows elements with similar properties to appear at regular intervals. Predict the group of elements and their number of valence electrons that will combine in a 2:1 ratio to with sodium. A)bromine, chlorine, iodine, 7
B)
sulfur, selenium, polonium, 6
Eliminate
C)
hydrogen, fluorine, potassium, 1
D)
calcium, phosphorus, tellurium, 2

Answers

The correct option is B.

Sodium will react with elements in GROUP 6, WHICH HAVE SIX ELECTRONS IN THEIR OUTERMOST SHELLS.

Sodium is a metal with atomic number 11. The electronic configuration of sodium is 2,8,1. This implies that, sodium has one electron in its outermost shell. Sodium always donate this electron in order to become stable. Elements in group 6 have six electrons in their outermost shells and they require two more electrons to attain stability. In order to form chemical bonds with elements from group 6, two atoms of sodium will react with each atom of those elements, that is, the ratio of reaction will be 2:1. By so doing, the two sodium atoms will be the ones that will donate the two electrons that the group 6 elements need to attain stability. One example of compounds formed by such reaction is sodium sulfide, Na2S.

The main part of this question is the "2:1 ratio."

On the periodic table, bromine, chlorine, and iodine have 7 valence electrons and sulfur, selenium, and polonium have 6, so these choices are viable based on their valence electrons. However, fluorine does not have 1 valence electron and phosphorus and tellurium do not have 2 valence electrons, so C) and D) are automatically out, leaving A) and B).

If we know that the sodium will combine in a 2:1 ratio, we know that the charge of the ions must have a 2:1 ratio too; that's how ionic compounds work. Sodium (Na) has an ion with a charge of +1 (Na+), so that means whatever ion it combines with in a 2:1 ratio must have a charge of -2   -   a 2:1 ratio.

Bromine, chlorine, and iodine have a charge of -1, but sulfur, selenium, and polonium have charges of -2. This gives us the correct answer as C).

What type of bonds form salt crystals

Answers

For the answer to the question above, I believe it is anA ionic bond because NaCl is a bond between a metal and a non-metal. Na has a +1 charge and Cl has a -1 charge, therefore there is an exchange of ions between both elements to achieve a stable configuration.

What is observed when an iron bar is dipped into a solution of silver nitrate​

Answers

Answer:

I think it will start to have a greenish color and get lighter

Explanation: