Which shows the dimensions of two rectangular prisms that have volumes of 72 cm3 but different surface areas? A. 6 cm by 3 cm by 4 cm; 12 cm by 2 cm by 3 cm B. 2 cm by 4 cm by 9 cm; 9 cm by 4 cm by 2 cm C. 3 cm by 3 cm by 8 cm; 2 cm by 6 cm by 8 cm D. 6 cm by 3 cm by 4 cm; 9 cm by 4 cm by 3 cm
Answers
V=l*w*h
A.
6*3*4=72cm³
12*2*3=72cm³
B.
2*4*9=72cm³
9*4*2=72cm³
C.
3*3*8=72cm³
2*6*8=96cm³
D.
6*3*4=72cm³
9*4*3=108cm³
We can conclude that C & D aren't the answer, since they contain prisms that don't have a volume of 72cm³.
Now lets solve for the surface area of A and B...
A.
sA=2(wh+lw+lh)=2(6*3+4*6+4*3)=2(18+24+12)=2(54)=108cm²
sA=2(wh+lw+lh)=2(12*2+3*12+3*2)=2(24+36+6)=2(56)=112cm²
B.
sA=2(wh+lw+lh)=2(2*4+9*2+9*4)=2(8+18+36)=2(62)=124cm²
sA=2(wh+lw+lh)=2(9*4+2*9+2*4)=2(36+18+8)=2(62)=124cm²
A is the only option with both similar volumes of 72cm³ and different surface areas...
Answer=A
Answer:
A
Step-by-step explanation:
A, is the answer
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First, let us review what a linear first-order differential equation is. Ais a differential equation that can be written in the form:
a1(x) dy/dx + a0(x)y = f(x)
Now, let us compare the given differential equation to the standard form of a linear first-order differential equation. The given differential equation is:
a1(x) dy/dx + a0(x)y
As we can see, the given differential equation matches the standard form of a linear first-order differential equation. Therefore, we can conclude that the given differential equation is linear in the indicated dependent variable.
In conclusion, the given first-order differential equation is linear in the indicated dependent variable because it matches the standard form of a linear first-order differential equation, a1(x) dy/dx + a0(x)y = f(x).
To know more about linear first-order differential equation, click the link below :
brainly.com/question/30645878#
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