Show a way to count from 170 to 410 using tens and hundreds. circle at least 1 benchmark number

Answers

Answer 1
Answer: Okay, so we start at 170

170

then we add 30 to reach the number 200

170+30=200

then we add 200 to reach the number 400

200+200=400

then we add 10 to reach 410

400+10=410

The benchmark numbers are bolded...

Related Questions

For the data in the table, does y vary directly with x? If it does, write an equation for the direct variationx y10 1215 1820 24
Solve for x. 12:15 = x:5
Find n. 2/9=14/n n=_____
4.(01.03) Suppose you are going to graph the data in the table below. What data should be represented on each axis, and what would be the appropriate increments? (2 points) Reporting periods Sales Jan.–Mar., 2010 $100,000 Apr.–Jun., 2010 $55,000 Jul.–Sep., 2010 $45,000 Oct.–Dec., 2010 $110,000 Jan.–Mar., 2011 $330,000 Apr.–Jun., 2011 $800,000 Jul.–Sep., 2011 $242,000 Oct.–Dec., 2011 $150,000 x-axis: time period in increments of 1 month; y-axis: sales in increments of $1,000 x-axis: sales in increments of $1,000; y-axis: time period in increments of 1 month x-axis: time period in increments of 3 months; y-axis: sales in increments of $100,000 x-axis: sales in increments of $100,000; y-axis: time period in increments of 3 months
In the diagram ce =12 and be=5 based on the given info ae =

Based on the information below, what are the values of x and y of the solution to the system of equations used to create the information? [A]=[4 -6 8 -2][Ax]=[38 -6 26 -2][Ay]=[4 38 8 26]x = -5, y = 2
x = -0.2, y = 0.5
x = 0.5, y = -0.2
x = 2, y = -5

Answers

The correct option is D. x = 2, y = -5. The values of x and y of the solution to the system of equations are 2, -5.

When solving a set of equations in mathematics, a matrix is a collection of integers or expressions.

The matrix A is

[A]=[4 -6 8 -2]

The matrix Ax is

[Ax]=[38 -6 26 -2]

The matrix Ay is

[Ay]=[4 38 8 26]

All of the matrices' determinant is

|A| = 40

|Ax| = 80

|Ay| = -200

The value of x is (|Ax|) /(|A|) = 80/(40) = 2

The value of y is ( |Ay|)/(|A|) = -200/(40) = -5

Therefore, the value of x and y is 2, -5. The correct option is D

Learn more about system of equations here

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Round this number to the nearest hundred.
728

Answers

700 is the answer......

What is the average of 37, 22, 52, 17, 16, and 25

Answers

28.1666666666666.....

Before embarking on a flight, the pilot of a private airplane plans the best route to the finaldestination. Suppose the pilot determines one route covers a distance of \sqrt{500 miles and another covers a distance of [tex] \sqrt{605} miles

a. a. Write an expression to represent the difference between the two distances of
each route. Then simplify the expression, keeping your answer in radical form.
Show all steps needed to write your answer in simplest form.

b.b. Use a calculator to change the answer to decimal form. Round the answer to the
nearest tenth. Using this decimal number, write a sentence to explain the
meaning of the answer in this situation.

Answers

Differ of these distances:

√(605) - √(500)

Simplify this distance:

√(605)  - √(500) = √(121 \cdot 5) - √(100 \cdot 5)= √(121) \cdot √(5)-√(100) \cdot √(5)= \n \n = 11√(5)-10√(5)=√(5)

To a decimal form:  √(5) \approx 2.2

Meaning of the answer?  The answers  2.2  or √(5) is just very clear to  us  

What are the greatest Common factor of 28 and 32

Answers

The factors of 28: 1; 2; 4; 7; 14; 28
The factors of 32: 1; 2; 4; 8; 16; 32

GCF(28; 32) = 4

WORTH 50!! Answer it with explanation and the answer is not y+6 I have some idea on how to do this.

Answers

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34

Step-by-step explanation:

Given:

2x-3y=12

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

2x-3y=12  

Solution:

2x-3y=12...........Given

\therefore y=(2)/(3)* x-4

Comparing with,  

y=mx

Where m =slope  

We get

Slope = m1 = (2)/(3)

We know that for Perpendicular lines have product slopes = -1.

m1* m2=-1

Substituting m1 we get m2 as

m2=-(3)/(2)

Therefore the slope of the required line passing through (16 , -7) will have the slope,

m2=-(3)/(2)

Now the equation of line in slope point form given by

(y-y_(1))=m(x-x_(1))

Substituting the point (16 , -7)  and slope m2 we will get the required equation of the line,

(y-7)=-(3)/(2)* (x-16)\n\n2y+14=-3x+48\n3x+2y=34......Equation\ of\ line

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34