The graphs that match the function given are:
(a) VI, (b) III, (c) I, (d) II, (e) V, (f) IV
Consider the equations of the graphs given :
(a) y = 0.5 x²
This is a quadratic equation and thus will be a parabola.
This matches VI.
y is directly proportional to the square of x.
(b) y = 5/x²
Here negative values of y are not possible since x is squared.
Also, the values of y will be equal to a and -a.
This matches III.
y is inversely proportional to the square of x.
(c) y = x³
Here negative values of x will have the y values also negative.
Also, the value increases when x increases.
This matches I.
y is directly proportional to the cube of x.
(d) y = 1/x³
y value for x = -a is the negative of the y value for x = a.
Also, as x increases y decreases.
The function is not defined at 0.
This matches II.
y is inversely proportional to the cube of x.
(e) y = 3√x
Here since x is inside the cube, not defined for negative values of x.
As x increases, y also increases.
This matches V.
y is directly proportional to the square root of x.
(f) y = (0.5)ˣ
For negative values o x, the value of y will be high and for positive values of x, the value of y will be lower.
This matches IV.
y is exponentially related to x.
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B. Above par
C. On par
D. Par equality
The Correct Answer Is B- Above Par
Greg has 40 CD's and 20 DVD's. He sold 10 DVDs and 1/8 of his CD(40/8 = 5).
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
It is given that:
Initially, Greg has a total of 60 DVDs and CDs in his collection.
He then sold 1/8 of his CDs and 1/2 of his DVDs.
Let the number of CD is c and DVD is d
c + d = 60
2(c/8) = d/2
d = 60 - c
4(2c/8) = 4(60-c)/2
c = 120 - 2c
c = 40
d = 60-40 = 20
Thus, Greg has 40 CD's and 20 DVD's. He sold 10 DVDs and 1/8 of his CD(40/8 = 5).
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Answer:
10 DVD's were sold.
Step-by-step explanation:
c = number of CD's
d = number of DVD's
so we know:
c + d = 60
2*c/8 = d/2
this can be solved:
d = 60 - c
2c / 8 = (60-c)/2
4*(2c/8) = 4*(60-c)/2 [multiply by 4]
c = 120 - 2c
3c = 120
c = 40
d = 60-40 = 20
So Greg had 40 CD's and 20 DVD's. He sold half of his DVD's, i.e., 20/2=10 and 1/8 of his CD, i.e., 40/8 = 5