True. The balanced equation: 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O represents the combustion of ethane (C₂H6).
A substance (often a hydrocarbon) combines with oxygen (O₂) in a combustion reaction, resulting in the major byproducts of carbon dioxide (CO₂) and water (H₂O). According to the equation, four molecules of carbon dioxide (CO₂) and six molecules of water (H₂O) are produced when two molecules of ethane (C₂H₆) and seven molecules of oxygen (O₂) react.
The number of atoms in each element is equal on both sides of the reaction arrow, indicating that the equation is balanced. This guarantees that the law of conservation of mass—according to which, in a chemical reaction, mass is never created nor destroyed—is upheld.
In conclusion, the combustion of ethane is accurately represented by the following balanced equation.
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2C2H6 + 7O2 → 4CO2 + 6H2O
C2H6 is ethane,
Ethane reacts with oxygen, so it is the combustion.
The equation is balanced.
Answer is True.
What elements as a in stainless steel?
And how (%) of each element
Just answer one question if u want
Answer:
See the answer and the resolution below
Explanation:
The equation of the decomposition of magnesium carbonate is as follows:
Mg C03 (white solid) ---> C02 (gas) + Mg= (solid)
To calculate the mass of carbon dioxide produced, the weight of 1 mol of this and 1 mol of MgC03 is calculated. Then a simple rule of 3 is made.
Weight 1 mol of MgC03= Weight Mg + Weight C+ 3x(Weight 0)= 24,305g+ 12,017+3x (15,999)= 84, 318g/mol
Weight 1 mol of C02= Weight C + 2x(Weight 0)=12,017+2x (15,999)= 44, 008g/mol
84, 319 g MgC03------44,008g C02
36,0 g MgC03------X= (36,0 g MgC03x44,008g C02)/84, 319 g MgC03= 18,8 g C02