Hey guys I'm pretty sure I got the first two questions but if I didn't can you help me and I need help with the last two questions.
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the adjacent angle i think is EOH
Related Questions
In the diagram below, the top of each stair is parallel to the floor. What is the value of y?(Picture below.)
Geometry..they all look correct? But there isn't an all the above..so..
Match the result of solving an equation to the number of solutions the equation has3 = 3no solution6 = 3infinitely many solutionsone solutionx=3
if i get the fraction "2/2" and i need to reduce it would it be "1" or "2" like would it be 2 wholes or only 1??
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Answer:
Use the slope-intercept form to find the slope and y-intercept.
Slope: −1 y-intercept: (0,−5)
Step-by-step explanation:
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Answer:
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Volume of cylinder = 2πr²×h
So:
75 = 2πr²×3
12.5 = πr²
r = 1.99(471140201)
A = 2π×1.99×3+2π×1.99²
= 62.39(265842) ft²
Final answer:
The surface area of a given cylinder with a volume of 75 cubic feet and a height of 3 feet is calculated to be 80 square feet by first finding the radius from the volume and height, then substituting those into the surface area formula.
Explanation:
To find the surface area of a cylinder, we first need to know the radius. Given the volume (V) of a cylinder is 75 cubic feet and the height (h) is 3 feet, we can use the formula V = πr²h to find the radius (r). Now, since V = 75 cubic feet and h = 3 feet, we can adjust our formula to solve for r: r = √(V/(πh)) = √(75/(3π)) and find the radius to be 2.88 feet. The formula for the surface area (SA) of a cylinder is SA = 2πrh + 2πr². Substituting r = 2.88 feet and h = 3 feet, we calculate the surface area to be 80 square feet. So the answer is H: 80 square feet.
Learn more about Cylinder Surface Area here:
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You're working with two right triangles here.
The big one is the whole drawing. It's lying flat on its hypotenuse.
One side of the big triangle ... the left side ... has no label.
We'll be working with that side. Let's call it ' S ' .
The smaller triangle is the left piece of the big one.
Its height is 'y', and its base is 4. ' S ' is its hypotenuse.
Go to your toolbox and pull out the little box marked "Pythagoras".
Inside that box is the equation you need in order to work on this
problem, or any problem with right triangles. The equation is ...
(hypotenuse)² = (length of one leg)² + (length of the other leg)² .
In the big triangle, 'x' is one leg, and the hypotenuse is 16 .
(16)² = x² + S²
256 = x² + S²
Subtract x² from each side: S² = 256 - x²
Take the square root of each side: S = √(256 - x²)
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Now look at the small right triangle.
One leg is 4. The other leg is 'y'. The hypotenuse is ' S '.
S² = (4)² + y²
Subtract 16 from each side: y² = S² - 16
Writer in the value of S² that
we worked out before: y² = (256 - x²) - 16 .
y² = 240 - x²
Take the square root
of each side: y = √(240 - x²) .
That's what you're supposed to find. So we're done.
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Oh phooey ! Sometimes I am so stupid.
Forget almost everything I did up above, and
let's back up several steps:
==> Cut the picture along the line marked 'y', and throw away
the left piece, with the '4' on the bottom. We don't need it.
-- Now you have a right triangle that I didn't even notice before.
One leg is 12. The other leg is 'y'. The hypotenuse is 'x'.
Pythagoras says: (x²) = (12²) + (y²)
Subtract 12² from each side: y² = x² - 144
Take the square root of each side: y = √(x² - 144) .