Answer:
Option (1), (2) and (3)
Explanation:
The subduction zones are created when a denser oceanic plate subducts under a lighter continental or oceanic plate. It forms at the convergent plate boundary. The point above this subduction zone where the depression forms is known as the oceanic trenches. This trenches extends up to a great depth. The subducting plates undergoes partial melting as a result of which the plate melts and the magma rises up towards the over-riding plate forming volcanoes or chain of volcano. This type of plate boundary generates deep focus earthquakes.
Thus, the correct answer are option (1), (2) and (3).
Subduction zones are regions where tectonic plates converge, often resulting in seismic activity, or earthquakes. They are typically located at ocean trenches and are frequently associated with volcanic arcs. Seafloor spreading, however, happens at mid-ocean ridges, not subduction zones.
Subduction zones are areas where one tectonic plate moves under another and sinks into the mantle as the plates converge. Three key characteristics typically define these zones. First, subduction zones are indeed areas of frequent earthquakes as the movement of the plates can cause significant seismic activity. Second, they occur at ocean trenches, which are the deepest parts of the ocean floor. Third, lines of volcanoes, known as volcanic arcs, often form near subduction zones as the subducted plate melts and forms magma, which can rise to the surface and create a volcano. However, the seafloor does not spread at subduction zones; this occurs at divergent boundaries, such as mid-ocean ridges.
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To calculate the noon sun's angle above the horizon at Placerita Canyon, identify today's date and find the corresponding solar declination using the analemma. Next, calculate the arc distance (AD) by subtracting this declination from 34°N, and finally subtract the AD from 90° to get the solar altitude (SA). This gives you the sun's angle above the horizon at noon.
To calculate the angle of the noon sun above the horizon at a location of approximately 34°N latitude, given that the solar altitude (SA) is 90º minus the arc distance (AD). Start with the latitude of 34°N. Identify today's date and find the corresponding declination of the sun using the analemma. Subtract this value from 34°N (or vice versa depending on which is greater) for the AD. Finally, subtract the AD from 90° to get the SA.
For example, if today's declination of the sun was 23°N: AD = 34°N - 23°N = 11°, then SA = 90º - 11º = 79º. So, at noon the sun would be 79 degrees above the horizon at Placerita Canyon if today's date corresponds to a declination of 23°N.
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Answer:
The latitude at which the noon sun is directly overhead is defined as the sun's declination. For example, if the sun appears directly overhead at 20°N latitude, the sun's declination is thus 20°N. Figure 7-3, known as analemma, shows the declination of the sun throughout the year. Thus, if you would like to know where the sun will be directly overhead on September 20, you can look on the analemma and find that it will be at 1°N. Given the declination, the noon sun angle at a particular latitude on any given day can be calculated.
Figure 7-3. The analemma, a graph illustrating the latitude of the overhead noon sun throughout the year.
Figure 7-4 shows that for each degree of latitude that the place is away from the latitude where the noon sun is overhead (declination), the angle of noon sun becomes one degree lower from being vertical (or 90°) above the horizon. Noon sun angle for any given latitude on any given day can be calculated using the following equation:
Noon Sun Angle = 90° - (Latitude +/- Declination)
In this equation, use " - " when the latitude and declination are on the same hemisphere and use " + " when they are on the opposite hemispheres. For example, on April 11, the declination is 8°N, the noon sun angle at Springfield, Illinois (40N) on April 11, therefore, should be 58° (90° - (40°N - 8°N).
Figure 7-4. Noon sun angle calculation. The example in this figure illustrates how to calculate the noon sun angle for a city 40° north of the equator (like Springfield, Illinois) on December 22.
Questions
Based on Figure 7-3, the sun shifts its position between which two important latitudes (find the terminologies for these two latitudes in Fig. 7-4). (2 points)
Using the analemma (Fig. 7-3), determine the declinations on each of the following dates. (6 points)
August 10 _________________
September 21 _______________
June 21 ______________
October 15 ____________
December 22 ______________
March 21 _________________
Calculate the noon sun angle in Grayslake, Illinois on each of the dates listed below. (6 points)
Noon Sun Angle in Grayslake on
August 10 _________________
September 21 _______________
June 21 ______________
October 15 ____________
December 22 ______________
March 21 _________________
Obtain the average temperature in Grayslake on each of the dates listed below using a weather station online. (6 points)
Average Temperature in Grayslake on:
August 10 ________________
September 21 _______________
June 21 _____________
October 15 ____________
December 22 ______________
March 21 _________________
Plot the noon sun angle and temperature on each of the dates you obtained in Questions 3-4 on the graph provided below and connect your temperature and noon sun angle plots using smooth lines. Discuss the relationship between noon sun angles and average temperature in Grayslake throughout the year based on your graph. Use the right vertical axis to show temperature variation from -30° F at bottom and +105° F on top (label temperature value at equal amount interval in between: 2 units for every 5°F). Use the left vertical axis to show noon sun angle, with 0° at the bottom and 90°F on top (label noon sun angle value at equal amount intervals in between: every 3 units per 10°). (4 points)
J F M A M J J A S O N D
Months
Figure 7-5. Variation of temperature and noon sun angle in Grayslake.
brief paragraph summarizing the yearly movement of the overhead noon sun and how the intensity of insolation aries in Grayslake throughout the year. (2 points)
Calculate the maximum, minimum, and average noon sun angles at the place in Grayslake. Show your calculations. (3 points)
Maximum noon sun angle:
Minimum noon sun angle:
Average noon sun angle:
When the noon sun is directly overhead a ship in the Pacific Ocean on October 16, the ship's latitude is _____________. Explain your answer. (2 points)
resource, not a renewable resource.
Answer: It is flow resource for as long as there is tidal and water movement then their will be energy but that doesn't last forever
Explanation:
Answer and Explanation:
Flow resources: water, wind and sunlight are neither renewable nor non-renewable because they can only be used when and where they are. The energy in a river can be used to generate electricity, but it must be captured by turbines or it will be lost.
A: A flow resource is a resource that there is a certain amount of on Earth. Water is not renewable because renewable is a resource that you use up and reproduce. You can not produce water, you just clean it and reuse it. Tidal power is water power so it is not renewable.
I hope this helps :)
B) westerlies
C) doldrums
D) polar easterlies
C Gulf of Baja
b. Pacific Ocean
d. Gulf of Mexico
Answer:
A:Gulf of california
i think that is your answer
Explanation:
Mexico is bounded to the north by the United States (specifically, from west to east, by California, Arizona, New Mexico, and Texas), to the west and south by the Pacific Ocean, to the east by the Gulf of Mexico, and to the southeast by Belize,Guatemala, and the Caribbean Sea.
Please select the best answer from the choices provided.
T
F
2. weather graphs
3. climographs
4. barographs
5. rain graphs
Answer:
3. climographs
Explanation: