Allison has a poster that is 15 in by 18 in. What will the dimensions of the poster be if she scales it down by a factor of 1/3

Answers

Answer 1
Answer: If you minus one third from 15 and one third from 18, the dimensions would be 10 x 12

15÷3 = 5
18÷3 = 6
15 - 5 = 10
18 - 6 = 12

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6 students shared 5 small pizzas equally

Answers


Bon apetit !  What more can I say ?

Was there a question ?

If your objective is to feed 6 students with 5 pizzas, then do it like this:

(5 pizza) / (6 student) = 5/6 pizza per student.

Cut each pie in 6 equal pieces, and give each student 5 of the pieces.




Answer and workings in the doc below.

Make c the subject of the formula:
A=b+cd

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The answer is c=(a/d)-b

What is the equation of the following graph in vertex form?the graph shows a positive parabola with the vertex at, (-1,0) and passes through (0,1) and (-2,1)
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y = (x − 1)2
y = (x − 1)2 + 1
y = (x + 1)2 − 1
y = (x + 1)2

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Vertex form uses the following formula:


a(x-h)^2 + k


a determines the stretch of the parabola. h and k are the x and y values of the vertex (h, k), respectively.


The vertex is at (-1, 0). There is no a value indicated for any answer. Plug these values into the equation:


\text{h = -1, k = 0}

(x - (-1))^2 + 0

\boxed{(x+1)^2}


The answer is (x+1)^2.

Answer:

(x+1)^2

Step-by-step explanation:

the difference between two positive integers is 40. one integer is three times as great as the other. find the integer.

Answers

Be the integers:  x and y

x - y = 40
x = 3y

Replace x in the first equation:

3y - y = 40
2y = 40
y = 20
x = 60

Solve by substitution
X+3y=1 and -3x-3y=-15

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x+3y=1\n -3x-3y=-15\n add\quad the\quad equ.\n (x+3y)+(-3x-3y)=1-15\n x-3x+3y-3y=-14\n -2x=-14\n x=\frac { -14 }{ -2 } \n x=7\n Let's\quad rewrite\quad the\quad equ.\n 7+3y=1\n 3y=1-7\n 3y=-6\n y=\frac { -6 }{ 3 } \n y=-2

Nick is solving the equation 3x^2=20-7x with the quadratic formula which values could He use for a, b and c

Answers

Answer:

C. a = 3

b = 7

c = -20

Step-by-step explanation:

x = -b+/- (sq) b^2 - 4ac.

Well the way to plug the numbers in is by using this equation: Ax^2 + Bx + C = 0

S if you use your equation : 3x^2 = 20 - 7x

First you have to move everything to one side.

So it'll look like this:

3x^2 = 20 - 7x

-20      -20

3x^2 - 20 = -7x

+7x  +7x

3x^2 - 20 + 7x = 0

don't forget that... Ax^2 +Bx+ C= 0

3 = A

7 = B

-20 = C