Name the postulate or theorem you can use to prove the triangles congruent.
A. SSS Postulate
B. SAS Postulate
C. ASA Postulate
D. AAS Theorem
Answer: D. AAS Theorem
Step-by-step explanation:
Given: ∠D ≅∠T, ∠E ≅ ∠U, EO ≅ UX
Then in Δ DOE and Δ TXU
∠D ≅∠T, [Angle]
∠E ≅ ∠U, [Angle]
EO ≅ UX [Side]
From the figure we can see they are two pair of corresponding congruent angles and one non included sides.
Thus by AAS theorem
Δ DOE ≅ Δ TXU
B. choices b and c only
C. choice c only
D. choices b, c, d only
A function is a relation in which every input value x has at most one output value y.
Consider all options:
a. Relation {(a, b), (a, c), (a, d), (a, e)} is not a function, because input value a has four different output values b, c, d and e.
b. Relation {(a, b), (b, b), (c, b), (d, b)} is a function, because every input value a, b, c and d have at most one output value b.
c. Relation {(a, b), (c, d), (e, f), (g, h)} is a function, because every input value a, c, e and g have at most one output value b, d, f and g, respectively.
d. Relation {(a, a), (b, c), (c, c), (d, e)} is a function, because every input value a, b, c and d have at most one output value a, c, c and e, respectively.
Answer: correct choice is D
Which expressions for Step 3 and Step 5 complete the derivation?
Step 3: Sine ( (StartFraction pi over 2 EndFraction minus x) + y )
Step 5: cos(x)cos(y) + sin(x)sin(y)
Step 3: Sine ( (StartFraction pi over 2 EndFraction minus x) + y )
Step 5: cos(x)cos(y) – sin(x)sin(y)
Step 3: Sine ( (StartFraction pi over 2 EndFraction minus x) minus y )
Step 5: cos(x)cos(y) + sin(x)sin(y)
Step 3: Sine ( (StartFraction pi over 2 EndFraction minus x) minus y )
Step 5: cos(x)cos(y) – sin(x)sin(y)
Answer:
Option (4)
Step-by-step explanation:
STEP - 1
cos(x + y)
STEP - 2
STEP - 3
STEP - 4
STEP - 5
cos(x)cos(y) - sin(x)sin(y)
[Since, and ]
[Since, cos(-x) = cos(x) and sin(-x) = -sin(x)]
Therefore, Option (4) will be the correct option.
Answer:
D
Step-by-step explanation:
Top Answer was right, don't know why it was rated poorly