Suppose that an airline uses a seat width of 16.7 in. Assume men have hip breadths that are normally distributed with a mean of 14.2 in. and a standard deviation of 0.9 in. Complete parts? (a) through? (c) below. A) Find the probability that if an individual man is randomly? selected, his hip breadth will be greater than 16.7 in. B) If the plane is filled with 126 randomly selected men find the the probability that these men have a mean hip breadth greater than 16.7. C) Which results should be considered for any changes in seat design: the result from part a or part b. TI84 use pleaese

Answers

Answer 1

Answer:

Using the normal distribution and the central limit theorem, it is found that:

a) 0.0027 = 0.27% probability that if an individual man is randomly selected, his hip breadth will be greater than 16.7 in.

b) 0% probability that these men have a mean hip breadth greater than 16.7.

c) The results of part a should be considered, as there would be a problem if many of the passengers could not fit in the seats.

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Normal Probability Distribution

In a normally distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

The z-score measures how many standard deviations the measure is from the mean.
Each z-score has a respective p-value.
This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

The mean is of 14.2 in, thus $\mu = 14.2$
The standard deviation is of 0.9 in, thus $\sigma = 0.9$

Item a:

This probability is 1 subtracted by the p-value of Z when X = 16.7, so:

$Z = (X - \mu)/(\sigma)$

$Z = (16.7 - 14.2)/(0.9)$

$Z = 2.78$

$Z = 2.78$ has a p-value of 0.9973.

1 - 0.9973 = 0.0027.

0.0027 = 0.27% probability that if an individual man is randomly selected, his hip breadth will be greater than 16.7 in.

Item b:

By the Central Limit Theorem, the standard deviation of the sampling distributions of sample means of size n is: $s = (\sigma)/(√(n))$ .
Sample of 126, thus $n = 126, s = (0.9)/(√(126))$ .

$Z = (X - \mu)/(s)$

$Z = (16.7 - 14.2)/((0.9)/(√(126)))$

$Z = 31.2$

$Z = 31.2$ has a p-value of 1.

1 - 1 = 0

0% probability that these men have a mean hip breadth greater than 16.7.

Item c:

The results of part a should be considered, as there would be a problem if many of the passengers could not fit in the seats.

A similar problem is given at brainly.com/question/24342706

Answer 2

Answer:

Answer:

a) 0.003

b) 0.00001

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.2

Standard Deviation, σ = 0.9

We are given that the distribution of hip breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_(score) = \displaystyle(x-\mu)/(\sigma)$

a) P(hip breadth will be greater than 16.7)

P(x > 16.7)

$P( x > 16.7) = P( z > \displaystyle(16.7 - 14.2)/(0.9)) = P(z > 2.77)$

$= 1 - P(z \leq 2.77)$

Calculation the value from standard normal z table, we have,

$P(x > 16.7) = 1 - 0.997 = 0.003$

b) Standard error due to sampling

$=\displaystyle(\sigma)/(√(n)) = (0.9)/(√(126)) = 0.0802$

a) P(hip breadth will be greater than 16.7 for the sample)

P(x > 16.7)

$P( x > 16.7) = P( z > \displaystyle(16.7 - 14.2)/(0.0802)) = P(z > 31.17)$

$= 1 - P(z \leq 31.17)$

Calculation the value from standard normal z table, we have,

$P(x > 16.7) \approx 0.000001$

c)Result in a) should be considered for any changes in seat design because we need to consider the whole population and not the result for a sample.

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Answers

Convert the equation of the line to the slope-intercept form:
$4x+3y=60 \n3y=-4x+60 \ny=-(4)/(3)x+20$

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$x\ \textgreater \ 0 \ny\ \textgreater \ 0 \ny\ \textless \ -(4)/(3)x+20$

You can see all coordinates in your choices are positive, so the first two inequalities are satisfied. We must check which points satisfy the third inequality.
Plug the values (x,y) into the inequality and check:
$(2,18) \n18 \ \textless \ -(4)/(3) * 2+20 \n18 \ \textless \ -(8)/(3)+20 \n18\ \textless \ -2(2)/(3)+20 \n18\ \textless \ 17 (1)/(3) \nfalse \n \n(5,12) \n12\ \textless \ -(4)/(3) * 5+20 \n12\ \textless \ -(20)/(3)+20 \n12\ \textless \ -6(2)/(3)+20 \n12\ \textless \ 13 (1)/(3) \ntrue$

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Reduce 7y + 2y 2 - 7 by 3 - 4y?

Answers

(7y+2y2−7)−(3−4y)

=7y+4y+2y2−7−3

=11y−2y2−10

Hope this helps

Solve the rational equation

1/x+3/8=1/4

Answers

Step 1: Subtract 3/8 from both sides
1/x+3/8-3/8=1/4-3/8
1/x=1/4-3/8

Step 2: Multiply 1/4 by 1/2
1/x=(1/4)(1/2)-3/8
1/x=2/8-3/8

Step 3: Subtract
1/x=-1/8

Step 5: Multiply by x on both sides
1/x(x)=-1/8(x)
1=-1/8x

Step 6: Divide -1/8
1/(-1/8)=-1/8x/(1/8)
*You can times flip
1(-8)=-1/8x(8)
-8=-x
*Divide by -1
-8/-1=-x/-1
8=x

If the base lengths of the prism are doubled, how will the volume be affected?A) it will be multiplied by 2

B) it will be multiplied by 3

C) it will be multiplied by 4

D) it will be multiplied by 6

Answers

the answer is C). this is bc the volume of a prism is V=BH. the base is comprised of its length and width so if you double both of them the resulting volume is 4 times as large

I think the answer is CA cube with side lengths of 22×2×2=84×4×2=32À cube with side lengths of 44×4×4=648×8×4=256

Two blocks are connected by a very light string passing over a massless and frictionless pulley. The 20.0 N block moves 75.0cm to the right and the 12.0 N block moves 75.0cm downward.Find the total work done on 20.0N block if there is no friction between the table and the 20.0N block.

Answers

The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
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and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)

[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²

Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
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Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
Units have to be consistent ... so have to convert 75.0 cm to m:

75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J

Final answer:

The total work done on the 20.0 N block as it moves 75.0 cm to the right, with no friction between the table and the block, is 15 Joules.

Explanation:

In physics, work done by a force is given by the formula Work = Force x Distance x Cos θ, where θ is the angle between the force and the direction of motion. Here, the force is the same as the weight of the 20.0 N block (because weight = mass * gravity, and the mass is the weight divided by gravity, so mass * gravity = weight), and because the block moves horizontally (rightward), θ is 0 degrees. The Cos of 0 degrees is 1.

So, the work done on the 20.0 N block as it moves 75.0 cm (or 0.75 meters, because 1 m = 100 cm) to the right is 20.0 N * 0.75 m * 1 = 15 Joules.

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How do I round 35.26 to the nearest whole
number

Answers

The rounding off the nearest number gives 35.

What is rounding of a number?

A rounded number has about the same value as the number you start with, but it is less exact.
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up. Example: 38 rounded to the nearest ten is 40.
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down. Example: 33 rounded to the nearest ten is 30.

Given is the number 35.26.

We have the number as -

35.26

Rounding off, we get -

35.26

35.3

Therefore, the rounding off the nearest number gives 35.

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The rounded number to nearest whole number of 35.26 will be 35.

This is because we consider lower limit if the decimal is lower than 5, and consider the upper limit when the decimal is greater than 5.

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