By using relation between standard deviation and variance we got that sample with 0.75 variance has a standard deviation that is greater than the variance
Standard deviation is a number used to tell how measurements for a group are spread out from the average (mean), or expected value
Here we have to find a sample with standard deviation greater than the variance.
We know that Standard deviation is the square root of the variance so if we want a sample with greater Standard deviation than the variance then it's variance should be less than one as we know that if
And here given variances are
2.25, 1.75,0.75 and 1.25
Hence 0.75 is correct answer
By using relation between standard deviation and variance we got that sample with 0.75 variance has a standard deviation that is greater than the variance
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b. speed.
c. direction.
d. velocity.
Answer:
11²= 121
5³= 125
2⁷= 128
Step-by-step explanation:
The whole numbers can be multiplied with themselves to get numbers between 120 and 130 .
For example
11*11= 121
This can be written in the exponent form as
11²= 121 which is between 120 and 130.
Also
5*5*5= 125 or
5³= 125 which is also between 120 and 130.
and
2*2*2*2*2*2*2= 128
2⁷= 128 which is between 120 and 130 as required.
We see that as the powers or exponent increases the whole number is decreased.
76 is 10 percent of 7.6
I hope that's help !
Solve for p.
The value of the p is Q/(r + s) or the expression Q = p(r + s) can be written as p = Q/(r + s) after making subject as p.
It is defined as the combination of constants and variables with mathematical operators.
It is given that:
The expression is:
Q = p(r + s)
To solve for the p make the subject as p:
As we know, the arithmetic operation can be defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has basic four operators that are +, -, ×, and ÷.
Divide by (r + s) into both sides in the given expression where r + s ≠ 0
Q/(r + s) = p
Or
p = Q/(r + s)
Thus, the value of the p is Q/(r + s) or the expression Q = p(r + s) can be written as p = Q/(r + s) after making subject as p.
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