2.00 A
they want me to put an explanation but im not bout to do that uhnuhn
The minimum dimensions for the rear-view mirror should be a height of 0.890 m and a width of 1.3 m.
In order for the driver to be able to see the entire width and height of the rear window in the rear-view mirror without moving their head, the mirror should have minimum dimensions that allow for this visibility. Let's calculate the minimum height and width required for the rear-view mirror.
Height of the mirror:The mirror should be half the height of the driver, which is given as 1.715 m at the top and 0.825 m at the bottom. Therefore, the height of the mirror should be 0.890 m (1.715 m - 0.825 m).Width of the mirror:The mirror should be wide enough to capture the entire width of the rear window. The width of the rear window is given as 1.3 m, so the width of the mirror should be at least 1.3 m. Therefore, the minimum dimensions of the rear-view mirror should be a height of 0.890 m and a width of 1.3 m.#SPJ12
ball drops 45m under g=10m/s/s
45=1/2x10xt^2 ... application of kinematic equaion from rest
90/10=t^2
t=3
24.0 m in 3 secs => 8m/s no air resistance
The ball's initial speed is calculated using the principles of projectile motion. First, the time it takes for the ball to hit the ground is found using the vertical distance and acceleration due to gravity. the initial speed to be approximately 7.9 m/s.
The problem describes a case of projectile motion, a common topic in physics. Since the ball is thrown horizontally, the initial vertical velocity of the ball is zero. We're given that the horizontal distance covered is 24.0 m and the vertical distance is 45.0 m.
Because the horizontal and vertical motions are independent, we can use the equations of motion to solve the problem. First, we have to find the time it takes for the ball to hit the ground. Using the equation of motion
"y = 0.5*g*t²",
where y = 45 m is the vertical distance, g = 9.8 m/s² is the acceleration due to gravity, and t is the time in seconds. Solving for t gives us the square root of (2*y/g), which is approximately 3.03 seconds.
Second, we use this time to find the initial speed of the ball. The horizontal distance covered x = 24.0 m is equal to the product of the time it's been travelling and its initial horizontal speed (v = x/t). Using the time from the previous step, we can find the initial speed to be approximately 7.9 m/s.
#SPJ2
B. One space probe has more air resistance than the other.
C. Only one space probe is exerting a gravitational force on the other.
D. One space probe is closer to Jupiter than the other
Answer:
The correct answer is D
Explanation:
Answer:
Amplitud = 2 m
wavelength = 35 m
Explanation:
The waves are described by an equation of the form
Y = A sin (kx -wt)
With k = 2 π/λ
With A is the amplitude of the wave, λ the wavelength and w the velocity
If we analyze the reporter's data, the maximum height of the value from zero to the highest, which corresponds to the amplitude of the wave
The other value 35 m between each wave corresponds to the distance between the ridges that is equivalent to the wavelength