Answer:
see below for the working
Step-by-step explanation:
Dividing by a number is the same as multiplying by the inverse of that number.
Answer:
The conclusion for this hypothesis test would be that the average American consumes less than or equal to 17 ounces of ice cream per month.
Step-by-step explanation:
We are given that Breyers is a major producer of ice cream and would like to test if the average American consumes more than 17 ounces of ice cream per month.
A random sample of 25 Americans was found to consume an average of 19 ounces of ice cream last month. The standard deviation for this sample was 5 ounces.
Let = average ounces of ice cream consumed by American per month
So, Null Hypothesis, : 17 ounces {means that the average American consumes less than or equal to 17 ounces of ice cream per month}
Alternate Hypothesis, : > 17 ounces {means that the average American consumes more than 17 ounces of ice cream per month}
The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;
T.S. = ~
where, = sample average = 19 ounces
s = sample standard deviation = 5 ounces
n = sample of Americans = 25
So, test statistics = ~
= 2
The value of the test statistics is 2.
Now at 0.025 significance level, the t table gives critical value of 2.06 at 24 degree of freedom for right-tailed test. Since our test statistics is less than the critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.
Therefore, we conclude that the the average American consumes less than or equal to 17 ounces of ice cream per month.
Answer:
9x9+6 could be possible
Step-by-step explanation:
Hope this is what you were looking for, have a great day (;
Answer:
Option E, two-proportion z test should be used to determine whether these data provide sufficient evidence to reject the hypothesis that the proportion of shoppers at the suburban mall who had been to a movie in the past month is the same as the proportion of shoppers in the large downtown shopping area who had been to a movie in the past month
Step-by-step explanation:
The complete question is
In a random sample of 60 shoppers chosen from the shoppers at a large suburban mall, 36 indicated that they had been to a movie in the past
month. In an independent random sample of 50 shoppers chosen from the shoppers in a large downtown shopping area, 31 indicated that
they had been to a movie in the past month. What significance test should be used to determine whether these data provide sufficient
evidence to reject the hypothesis that the proportion of shoppers at the suburban mall who had been to a movie in the past month is the same
as the proportion of shoppers in a large downtown shopping area who had been to a movie in the past month?
A one-proportion z interval B two-proportion z interval
B two-proportion z interval
C two-sample t test D one-proportion z test
D one-proportion z test
E two-proportion z test
Solution
Two proportion z test is used to compare two proportions. In this test the null hypothesis is that the two proportions are equal and the alternate hypothesis is that the proportions are not the same. The random sample of populations serve as two proportions.
Hence, option E is the best choice of answer
Answer:
(a + b + c)/2
Step-by-step explanation:
Number of kids in first class: a
Number of kids in second class: b
Number of kids in third class: c
The total number of kids in all classes is: a + b + c
The total number of kids is divided equally between 2 buses:
(a + b + c)/2
Answer:
(a + b + c)/2
Step-by-step explanation:
;)
Answer:
His daily fat intake is 40.824g.
His daily Vitamin D intake is 290.304 IU.
Step-by-step explanation:
The first step to solve this problem is finding the daily kcal intake of the dogs.
Each cup has 324 kcal, and he eats 3.5cups a day. So:
1 cup - 324 kcals
3.5 cups - x kcals
kcals.
His daily intake is of 1134 kcals.
The food contains 3.6 g of fat in 100 kcals of energy. what is his daily fat intake?
There are 3.6g of fat in 100 kcals of energy. How many g of fat are there in 1134 kcals?
3.6g - 100 kcals
xg - 1134 kcal
g
His daily fat intake is 40.824g.
The food contains 25.6 IU of Vitamin D3 in 100 kcals of energy. what is his daily Vitamin D inake?
Similar logic as above.
25.6IU - 100 kcals
x IU - 1134 kcal
IU
His daily Vitamin D intake is 290.304 IU.