The table shows the height of a plant as it grows. What equation in point-slope form gives the plant s height at any time? Let y stand for the height of the plant in cm and let x stand for the time in months. Time (months) Plant Height (cm) 3 15 5 25 7 35 9 45

Answers

Answer 1
Answer: Here Plant height = 5 * time

i.e. y = 5x which is the required equation.

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Jonathan has been on a diet since January 2013. So far, he has been losing weight at a steady rate. Based on monthly weigh-ins, his weight, w, can be modeled by the function w=-3m+205 where m is the number of months after January 2013a) How much did Jonathan weigh at the start of the diet?

b) How much weight has Jonathan been losing each month?

c) How many month did it take Jonathan to lose 45 pounds?

Show work plz

Answers

a)\ \ \ w(m)=-3m+205\n\nm=0\ \ \ - at\ the\ start\ of\ the\ diet\n \nw(0)=-3\cdot0+205=205\n \nAns.\ weigh\ at\ the\ start\ of\ the\ diet\ is\ 205\ pounds\n \nb)\ \ \ w(m+1)=-3(m+1)+2015=-3m-3+205=-3m+202\n \nw(m+1)-w(m)=-3m+202-(-3m+205)=\n \n=-3m+202+3m-205=-3\n \nAns.\ Jonathan\ has\ each\ month\ 3\ been\ losing \n \n w(m)=205-45=160\ \ \ \Rightarrow\ \ \ -3m+205=160\ \ \ \Rightarrow\ \ \-3m=-45\n \nm=15\n \nAns.\ 15\ month

During every soccer game that Ronald plays, he runs all over the field. In his last game, he played on a soccer field that was 69,300 square feet. There are 3 feet in a yard. What is the area, in square yards (sq yd), of the soccer field where Ronald played his last game? Group of answer choices 7,700 sq yd 23,100 sq yd 207,900 sq yd 623,700 sq yd

Answers

Answer:

The area of the soccer field where Ronald played his last game is 7,700 sq yd.

Step-by-step explanation:

From the question,

The area of the soccer field where Ronald played his last game was 69,300 square feet.

To determine the area, in square yards (sq yd), of the soccer field where Ronald played his last game, we will convert 69,300 square feet to square yards.

Also, from the question

There are 3 feet in a yard, that is, 3 feet = 1 yard

If 3 feet = 1 yard

∴ 3² square feet (ft²) will be equal to 1² square yard (yd²)

That is,

9 square feet = 1 square yard

Now,

If 9 square feet = 1 square yard

Then, 69,300 square feet will be

(69,300 square feet × 1 square yard) / 9 square feet = (69300/9 )square yards

= 7700 square yards (sq yd)

Hence, the area of the soccer field where Ronald played his last game is 7,700 sq yd.

If one letter is chosen at random from the word combed, what is the probability that the letter chosen will be a "d"? Fraction:

Decimal:

Percentage:

Likelihood of the event happening:

Answers

combed

The word combed has 6 letters, only 1 of which is the letter d.

So, the fraction is 1/6.

Dividing, if you round to the nearest hundredth, the decimal is 0.17.

Using the fraction again, if you multiply 1/6 by 100 to make it 100/6 and then round to the nearest hundredth, you get 16.67 %.

Likelihood of the event happening can be represented in any of the above ways shown above.

Six more than fives times a number (x) is at least 21. I need an inequality.

Answers

5n + 6 ≥ 21 would be the way to write this in math language.

It says that 5n + 6 is 21 or is more than 21.  The symbol ≥ says 21 or more in this case.

Find the value of x in the equation 2 x + 20 = 15 + 3 x .a. 16
b. 25
c. 1
d. –5

Answers

x=5 are you sure d) is -5 ?
2x+20=15+3x
x=5
GoodLuck!

Johnathan ran 5 days this week. The most he ran in one day was 3.5 miles. Write an inequality that shows the distance johnathan could of ran any day this week

Answers

An inequality that shows the distance Johnathan could of ran any day this week is:

x\leq 3.5

Solution:

Let "x" be the distance Johnathan can run any day of this week

Given that,

Johnathan ran 5 days this week. The most he ran in one day was 3.5 miles

Therefore,

Number of days ran = 5

The most he ran in 1 day = 3.5 miles

Thus, the maximum distance he ran in a week is given as:

distance = 5 * 3.5 = 17.5

The maximum distance he ran in a week is 17.5 miles

If we let x be the distance he can run any day of this week then, we get a inequality as:

x\leq 3.5

If we let y be the total distance he can travel in a week then, we may express it as,

y\leq 17.5