MATHEMATICS HIGH SCHOOL

Two arcades have different pricing structures. Arcade A costs $5 to enter and $0.60 per game. Arcade B costs $7 to enter and $0.40 per game. How many games do you have to play in order for the two arcades to be the same price?

Answers

Answer 1
Answer:

Answer:

you would have to play 10 games
Answer 2
Answer:

Answer:

10 games

Step-by-step explanation:

Let C be cost and x be number of games

Arcade A: C = 5 + 0.6x

Arcade B: C = 7 + 0.4x

for both arcades to be the same price, Both C's must be equal, hence we equate the right side of both equations:

5 + 0.6x = 7 + 0.4x   (subtract 5 fromboth sides)

0.6x = 7 + 0.4x - 5

0.6x = 2 + 0.4x  (subtract 0.4x from both sides)

0.6x - 0.4x = 2

0.2x = 2 (divide both sides by 0.2)

x = 2 / (0.2)

x = 10

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The vertices of a right triangle are (6, 2), (–2, –4), and (–2, y). What is the value of y?



A.
–4


B.
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C.
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D.
4

Answers

The answer should be C. 2
:P hope this helps you
The value of y is C. 2.

(6, 2), (-2, -4), (-2, 2)

You have a bag with 30 fireballs and another bag with 42 jolly ranchers. For a party, you want to repackage the candy into smaller bags, and you want each bag to have the same number of fireballs and jolly ranchers and. How many bags will you be able to make?

Answers

Answer: 6 bags 5 fire balls and 7 jolly ranchers in one bad

Step-by-step explanation:Ok so you got 30 fire balls 42 ranchers what you can do is see like wow more ranchers in a bag we know that hmm 42/6 is ya know 7 and that 6 does it go into 30 yeah it does 30/6=5 so you got 5 fire balls and 7 jolly ranchers is each bag with 6 bags

Answer:

6 bags

Step-by-step explanation:

The GCF of 30 and 42 is 6.

30/6 = 5

42/6 = 7

To use all candy, put 5 fireballs and 7 jolly ranchers in each bag. You will make 6 bags.

Tony had 1 1/2 gallons of orange juice. He drank 2/7 of the orange juice he had. How mucj orange juice did Tony drink?

Answers

Answer:

(3)/(7)gallon.

Step-by-step explanation:

Amount of orange juice Tony had  is 1(1)/(2) gallons.

Amount of orange juice drank by him is (2)/(7) of the orange juice he had.

To find the amount of orange juice Tony drink, we need to first convert the amount of orange juice Tony had in improper fraction, as the amount of juice he had is given in Mixed fraction.

So, amount of orange juice Tony had is 1(1)/(2) =(3)/(2) gallons.

Now, to find the amount of orange juice Tony drink, we need to multiply (3)/(2) and (2)/(7)

So, amount of juice Tony drink is (3)/(2)* (2)/(7)

=(3)/(7)

Hence, amount of orange juice Tony drink is (3)/(7) gallon.
change 1 1/2 into a improper fraction. then multiply across. so 2 times 3 over 7 times 2. which equals 6/14. then simplify to get 3/7 as your final answer.

If4 times the reciprocal of a number is 3 more than 5/2 times the reciprocal of that number find the number Show your work

Answers

x-number\nx\neq 0\n \n 4 \cdot \frac1x=3+\frac52 \cdot \frac1x\n \frac4x=3+\frac5{2x}\ / \cdot 2x\n 8=6x+5\n 6x=8-5\n 6x=3\ /:6\n x=\frac36=\frac12

1)

4·1/n = 3 + 5/2n

²⁾4/n = ²ⁿ⁾3 + 5/2n

8 = 6n + 5

6n = 8 - 5

6n = 3

n = 3⁽²/6

n = 1/2

(5,?) is on the line below. Find the other half of the coordinate.
y = 2/3x + 7

Answers

We need to plug 5 in place of x into the equation of the line and find the y-value.

y = (2/3)x + 7

y = (2/3)5 + 7

y = 10/3 + 7

y = 10/3 + 21/3

y = 31/3

y = 10 1/3

The point is (5, 10 1/3) OR (5, 31/3).
(x,y) = (5, ?), so x = 5. Substitute 5 into the function for x to find the value of y when x = 5. y = 2/3 (5) + 7 = (2 x 5) / 3 + 7 = 10/3 + 7 = 10/3 + 21/3 = 31/3, which equals 10 1/3 or 10.3 repeating.

Consider the following two circles. Circle P with center (-1, 2) and radius 3 and circle Q with center (3, 4) radius 5. What sequence of transformations will carry circle P onto circle Q? Select all that apply.A. Dilation centered at Q, followed by reflection across the y-axis
B. Dilation centered at P, followed by reflection across the y-axis and then the line y = -x + 5
C. Translation (x,y) -> (x+4, y+2), followed by dilation centered at Q
D. Dilation (x+y) -> (3/5x, 3/5y), followed by dilation centered at P
E. Reflection over x-axis followed by rotation of 270 degrees

Answers

Answer:

B. Dilation centered at P, followed by reflection across the y-axis and then the line y = -x + 5

Step-by-step explanation:

Circle P.

Centerat (-1, 2).

Radius of 3.

Circle Q.

Center at (3, 4).

Radius of 5.

To carry one circle onto the other, their centers and radius must be the same.

So, circle P must be shifted from (-1, 2) to (3, 4), that means the translation is 4 units to the right side and two units upside, this is the first transformation.

The second transformation must be about stretching the circle P, from a radius of 3 to a radius of 5.

Therefore, the right answer is B.

Answer: Option b and Option c
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