Last year at a certain high school, there were 132 boys on the honor roll and 90 girls on the honor roll. This year, the number of boys on the honor roll increased by 25% and the number of girls on the honor roll increased by 20%. By what percentage did the total number of students on the honor roll increase? Round your answer to the nearest tenth (if necessary).

Answers

Answer 1
Answer:

The percentage of increase of total number of students on the honor roll is obtained as 22.97%.

What is percentage?

A percentage is a value that indicates 100th part of any quantity.

A percentage can be converted into a fraction or a decimal by dividing it by 100.

And to convert a fraction or a decimal into percentage, they are multiplied by 100.

The number of boys and girls on the honor code last year is given as 132 and 90.

Then, the total number is 132 + 90 = 222.

When, the number of boys increased by 25%, it can be obtained as,

⇒ 132 + 25% × 132 = 165

And, the number of girls increased by 20% can be obtained as,

⇒ 90 + 20% × 90 = 108

Now, the total number of students is 165 + 108 = 273.

The percent increase can be obtained as follows,

Change in the total number ÷ Initial number × 100

⇒ (273 - 222) ÷ 222 × 100 = 22.97%

Hence, the percent value of the increase in the number is 22.97%.

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Answer 2
Answer:

Answer:

23

Step-by-step explanation:

or 2.8 but try 23 frist


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What is the solution for w in the equation? w + 1/2 = 1/4w + 2

Answers

After solving the equation, the value obtained for w will be equal to 2.

What are arithmetic Operations?

The four fundamental operations of arithmetic are addition, subtraction, multiplication, and division of two or even more items.

Included in them is the study of integers, especially the order of operations, which is important for all other areas of mathematics, notably algebra, data management, and geometry.

As per the data in the question,

The equation given in the question,

w + 1/2 = 1/4w + 2

Add similar terms,

w - 1/4w = 2 - 1/2

(4w - w)/4 = (4 - 1)/2

3w/4 = 3/2

w = 12/6

w = 2

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Answer:

w = 2

Step-by-step explanation:

Can u help me with this please

Answers

1. Turkey trot
2. Pumpkin pie
3. Family dinner
4. Mashed potatoes
5. Football
6. Wishbone
7. Cut the turkey
8. Beans (I can’t tell what the first emoji is)
9. Cornucopia
10. Black Friday

Answer:

1. turkey trolley

2. pumpkin pie

3. family dinner

4. smashed potatoes

5. football

6. wishbones

7. kill the turkey

8. green beans

9. corn you policeman xD

10. black friday

some of the stuff i know but i tried

Step-by-step explanation:

How do you get the answer 3a -5 from: -3a - (5-6a)?

Answers

The key here is to remember how to get rid of the parentheses.

The 'minus sign' ( - ) before the parentheses says that in order to
get rid of them, you have to change the sign of each term inside.

-3a - (5 - 6a) is the same as

-3a -5 + 6a

Add up the (-3a) and the (+6a) and you have +3a .

So the whole thing becomes 3a - 5 . 

-3a - (5-6a)=-3a-5+6a=3a-5

In division, a problem includes a divisor, a dividend and....

Answers

A quotient, which is the answer of the division.
quotient ,quotient ... i think

Prove that:{ \left( { e }^{ \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi  }{ 2 }  \right)  }  }  \right)  }  } }  } \right)  }^{ \ln { \left( \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi  }{ 2 }  \right)  }  }  \right)  }  } }  \right)  }  }=1

Show your workings.

Answers

{ \left( { e }^{ \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi }{ 2 } \right) } } \right) } } } } \right) }^{ \ln { \left( \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi }{ 2 } \right) } } \right) } } } \right) } }=1\n{ \left( { e }^{ \sqrt { { e }^{ \ln { \left( \frac { 1 }{ 1} \right) } } } } \right) }^{ \ln { \left( \sqrt { { e }^{ \ln { \left( \frac { 1 }{1 } \right) } } } \right) } }=1\n
{ \left( { e }^{ \sqrt { { e }^( \ln 1 ) } } \right) }^{ \ln { \left( \sqrt { { e }^( \ln 1 ) } \right) } }=1\n{ \left( { e }^( \sqrt 1 ) \right) }^{ \ln { \left( \sqrt 1 \right) } }=1\n{ \left( { e }^ 1  \right) }^( \ln 1 )=1\n e  ^( \ln 1 )=1\n1=1

A rectangle has perimeter 26 cm, and the length and width are both whole numbers. What is the greatest possible area this rectangle may have in square cm?

Answers

The length should be 7 while the breadth should be 6 to maximize the area.

Perimeter of the Rectangle

The perimeter of the rectangle is twice the sum of its length and breadth.

\rm{Perimeter = 2(length +breadth)

Area of the rectangle

the area of the rectangle is given as the product of its length and its breadth.

\rm{Area ={length* breadth

Given to us

Permeter = 26 cm

Perimeter

\rm{Perimeter = 2(length +breadth)

26 = 2(length +breadth)

13=(length +breadth)

Area of the rectangle

As we know that the area is given as the product of length and breadth. so, we need to find those numbers whose sum is 13. while their product gives us the maximum area.

Therefore, for the area to be maximum the length and breadth should be maximum.

1 * 12 = 12\n2* 11 = 22\n3* 10 = 30\n4* 9 = 36\n5* 8 = 40\n6* 7 = 42

Thus, the length should be 7 while the breadth should be 6 to maximize the area.

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