The required area of pentagon is 212.36 mm².
Area is the entire amount of space occupied by a flat (2-D) surface or an object's shape. The area of a plane figure is the area that its perimeter encloses. The quantity of unit squares that cover a closed figure's surface is its area.
Given that,
radius of pentagon = 9 mm
Since in pentagons there are 5 sides.
Therefore,
Area is = (5/4)x s² x tan(π/5)
Where s is the pentagon's length along one side.
Use the pentagon's radius to get s using the following calculation
since we already know,
S = 2x radius x sin(π/5)
When we enter the values ,
we obtain: s = 2 x 9 x sin(π/5)
= 14.56 mm.
We can now enter this value of s into the area formula as follows:
Area = (5/4) x s² x tan(π/5)
= 212.36mm².
Consequently, the regular pentagon's area with a 9 mm radius is roughly 212.36 mm²
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The area is calculated by using the formula A=(r^2)*n*sin(360/n)/2 where n is the number of sides which is 5 for pentagon and r is the radius which is 9 mm. So, using the formula, the answer is 51.4 mm^2.
Answer:
0.84
Step-by-step explanation:
Let the probability that a city bus is ready for service when needed is represented as P(ready)=77%=0.77
Let the probability that a city bus is ready for service and has a working radio be represented as P(ready and radio)=65%=0.65
probabilty that it has a working radio given that it is ready for service =
P(radio and ready)=P(ready and radio) ÷ P(ready)
=0.65÷0.77=0.84416
≈0.84 to the nearest tenth
3 hours
B.
1 hour
C.
30 hours
D.
20 hours