The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample of 15 random matches of the player is taken, the mean first-serve percentage is found to be 26.4%. The margin of error of the sample mean is 83.71%.
Answer:
See image
Step-by-step explanation:
Plato
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12
In a roll of a pair of fair dice, what is the probability of the outcome being either a multiple of 3 or an even number? Are these events mutually exclusive?
, mutually exclusive
, not mutually exclusive
, mutually exclusive
, not mutually exclusive
Solve this problem using a similar strategy.
A number is multiplied by 10. Then 32 is added to the product. This sum is then divided by 4. The answer is 28.
What was the original number?
b) x=-6+5 square root 2
c) x= -4+5 square root 2
d) x= -2+5 square root 2
The solution to the equation is x = -8 ± 5√2, the correct option is A.
A quadratic equation is what can be written in the form of ax²+bx+c=0
The quadratic equation is
(x + 2)² + 12(x + 2) – 14 = 0?
Let y = x+2
then the equation will be of the form
y² +12y -14 = 0
This in the form of ax² +bx+c =0
The formula for solving is,
y = -6 ± 5√2
x +2 = -6 ± 5√2
x = -8 ± 5√2
To know more about Quadratic Equation
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Answer:
The possible ages of the four grandchildren are a = 4, b = 19, c = 26, and d = 34
Step-by-step explanation:
The given parameters are;
The number of grandchildren in the family = 4
The product of the ages of the four grand children = 67184
The age of the youngest grandchild < 10
The age of the oldest grandchild = 30 + The age of the youngest grandchild
Let a represent the age of the youngest grandchild, and let b, and c represent the ages of the other two intermediate grandchild
Therefore, we have;
a < 10
The age of the oldest grandchild = a + 30 < 10 + 30
∴ The age of the oldest grandchild < 40
The product of the ages of the four grandchildren = a × b × c × (a + 30) = 67184
The factors of 67184 that are between 1 and 40 are;
1, 2, 4, 8, 13, 16, 17, 19, 26, 34, 38
Taking a = 8, we have;
The age of the oldest grandchild × The age of the youngest grandchild = a × (a + 30) = 8 × 38 = 342
Therefore. a × b = 67184/(a × (a + 30) = 196.44
Therefore, a ≠ 8
For a = 4, we have the age of the oldest grandchild = a + 30 = 4 + 30 = 34
The age of the oldest grandchild × The age of the youngest grandchild = a × (a + 30) = 4 × 34 = 136
Therefore. a × b = 67184/(a × (a + 30) = 494
We find that the other factors of 67184, which are 19 and 26 have a product of 494
Therefore, the possible ages of the four grandchildren are a = 4, b = 19, c = 26, and d = 34
To give, 4 × 19 × 26 × 34 = 67,184.
2 - 2i
Answer:
a+ib=2sqrt2(cos7pi/4+isin7pi/4)
Step-by-step explanation:
a+ib=r (cos theta+isin theta)
r=sqrt a^2+b^2
r=sqrt (2)^2 +(-2)^2
r=2sqrt 2
theta=tan^-1(y/x) or (a/b)
theta= tan^-1(-2/2)
theta=-45 degrees
Now, I know that theta is in the fourth quadrant because cos (x-value) is positive. So, I am going to subtract my value from 360 degrees.
360-45= 315
theta=315
I can convert degrees to radians (if need be): 315 times pi/180= 7pi/4
Theta=7pi/4 r=2sqrt2
Substitute: a+ib=2sqrt2(cos7pi/4+isin7pi/4) this is radian format
or... a+ib=2sqrt2(cos 315+isin315) this is degree format