The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample of 15 random matches of the player is taken, the mean first-serve percentage is found to be 26.4%. The margin of error of the sample mean is 83.71%.
Answer:
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Step-by-step explanation:
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What is the result of dividing 48a3 + 32a2 + 16a by 4a? A. 12a2 + 8a + 4 B. 12a2 + 4a + 8 C. 12a + 8 D. 12a2 + 4a + 4
The required quotient is 12a2 + 8a + 4. Option A is correct.
Quotient to be determined when dividing 48a3 + 32a2 + 16a by 4a.
The quotient is that value when quantity is divided by some value.
Here,
= (48a3 + 32a2 + 16a)/4a.
= 48a3/4a + 32a2/ 4a + 16a/4a)
= 12a2 + 8a + 16
Thus, the required quotient is 12a2 + 8a + 4. When dividing 48a3 + 32a2 + 16a by 4a.
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C. S is the midpoint of.
D. S is between R and T.