How many solutions are there to an inequality

Answers

Answer 1

Answer: I depends on the problem i believe.

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If you use $99.00 ÷ 11 to estimate $98.69 ÷11

Which expressions are equivalent to -3-(7.5+4)

Answers

-3-(7.5+4)
PEMDAS
P for Parenthesis
E for Exponents
M/D for Multiplication/Division
A/S for Addition/Subtraction
We should first clear the ones in parenthesis: (Oder Of Operations)
= -3-(11.5)
= -3-11.5
= -14.5
Basically -3-(11.5)

With a few calculations, Kenan estimated that the tank has a capacity of about 86,400 in.cubed. What is its capacity in cubic feet? Use three unit

multipliers.

Answers

(86,400 cubic inches) x (1 cubic foot / 1,728 cubic inches) = 50 cubic feet

Do the problem in the picture below!!!

Answers

W(-4,7); X(-2,1); Y(2,1); Z(4,4)

Multiply (-1/6) x (-1/5)
A) -1/11
B) -1/30
C) 1/30
D) 1/11

Answers

C is the answer.

Negative times a negative is a positive.

The answer would be 0.03 repeated but as a fraction it is 1/30 so it's "C". Hope I helped you out.

If g(x)=1.5x-3 ,determined if f(x) > g(x) when x = 4

Answers

Answer:

Step-by-step explanation:

hope this helps

Add three data values to the following data set so the mean increases by 10 and the median does not change. {42, 37, 32, 29, 20}

Answers

Sum of the numbers in the set: 42+37+32+29+20 =160

Current mean: 160/5 = 32

Median = the valvue of the middle = 32.

New mean: 32+10= 42.

Sum of numbers in the new set = 42*8 = 336

Difference: 336 - 160 = 176

I want to include 32, so that the new median stays in 32.

So the other two numbers must add 176 - 32 = 144

I will use a smaller number than 32 and the other greater (again in order to keep the same median.

I will choose 28 and 144 - 28 = 116.

So my three new numbers are 28, 32 and 116 and the new set is {116, 42, 37, 32, 32, 29,28, 20}

Checking:

Sum of the terms: 116+42+37+32+32+29+28+20 = 336

Mean = 336 / 8 = 42, which is 10 more than the original mean.

And the new median is (32+32)/2 = 32. The same of the original set.

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Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5A) y= -8/5 x - 3B) y= -8/5x+3C) 3x - 5y =0D) 5x-3y=0