What is the median of the sample

Answers

Answer 1

Answer: the median would be 35 because you would croos off all number until 1 number is left. In this case there are 2 number so you would add those numbers together and divide by the numbers there are which is 2. 30 + 40= 70 /2= 35.

Answer 2

Answer: The median of the data would be 35 because in the middle is 30 and 40 and in the middle of 30 and 40 is 35 hope i helped ;)

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Write an expression for the quotient of twelve divided by the sum of two times g and one

Answers

Answer:

12/2g + 1

Step-by-step explanation:

Answer:

12/2g + 1

trust me i know this

How many 3/8 cup servings are in a pitcher containing 6 3/4 cup of orange juice?

Answers

You can solve this problem in multiple ways, but you'll have to divide the total volume with the amount per servings to find the number of servings (makes sense logically if you think about it).

The first way is to just use the fractions given. This will usually be your method in handling this if you're not familiar with it.

Convert 6 3/4 into an improper fraction. To do this, we need to put the 6 into the numerator somehow. We can approach this by multiplying the whole number (6) with the denominator (4) and adding it to (3). Basically, 6 x 4 + 3 = 27. This will be our new numerator. If you are not familiar with this concept, please let me know.

Our new fraction for the total amount of juice is $(27)/(4)$ . Divide this with the amount per serving, $(3)/(8)$

$(27)/(4) / (3)/(8)$
We flip the second fraction over and multiply it.

$(27)/(4) * (8)/(3) = (9)/(1) * (2)/(1) = 18 servings$ (I crossed out common numbers here, unfortunately I don't know how to do that here so let me know if my explanation was not clear enough. I skipped a few steps.)

18 servings would be your answer.

Or you can convert 6 3/4 into decimal, which would be 6.75. 3/8 in decimal is .375 and you can do long division from there. That way is a bit more tedious in my opinion, but sometimes more convenient.

Cheers!

If someone could help me with this problem it'd be very much appreciated!! *sorry for the quality btw

Answers

Okay, lets write down what we do know...

4 out of the 12 cups are decaf, so the odds of selecting a decaf cup by random is 4/12 or 1/3

Alternatively 8 of the 12 cups are caffeinated, so the odds of selecting a caffeinated cup by random is 8/12 or 2/3

P(decaf)=1/3
P(caf)=2/3

But those odds are only for the first cup picked. The second cup has 4 probabilities...

1. Picking a decaf cup for the second time

2. Picking a decaf cup for the first time

3. Picking a caf cup for the second time

4. Picking a caf cup for the first time

So lets find the probability of each event...

1. Picking a decaf cup for the second time. If a decaf cup has already been picked, then the odds of drawing another one is 3/11

2. Picking a decaf cup for the first time. If a decaf cup hasn't already been picked, then the odds of drawing one is 4/11

3. Picking a caf cup for the second time. If a caf cup has already been picked, then the odds of drawing one is 7/11

4. Picking a caf cup for the first time. If a car cup hasn't already been picked, then the odds of drawing one is 8/11.

Okay, so now we can solve for the various possibilities.

1. Picking a decaf cup for the second time
1/3*3/11=3/33

2. Picking a decaf cup for the first time
2/3*4/11=8/33

3. Picking a caf cup for the second time
2/3*7/11=14/33

4. Picking a caf cup for the first time
2/3*8/11=16/33

Both cups were caffeinated, so neither were decaf.

Answer= Neither cup is decaf.

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