Dalton
B.
Rutherford
C.
Democritus
D.
Bohr
E.
Thomson
The scientist is E. Thomson.
In the late nineteenth century, physicist J.J. Thomson started trying different things with cathode beam tubes. Cathode beam cylinders are fixed glass tubes from which the greater part of the air has been emptied. A high voltage is applied crosswise over two terminals toward one side of the cylinder, which makes a light emission stream from the cathode (the contrarily charged anode) to the anode (the emphatically charged cathode).
The cylinders are called cathode beam tubes on the grounds that the molecule bars or “cathode beam” begins at the cathode. The beam can be distinguished by painting a material known as phosphors onto the most distant finish of the cylinder past the anode. The phosphors sparkles, or produces light, when affected by the cathode beam.
0.038 g He
From the question we are given;
Volume of the flask, V = 250 mL
Pressure of He, P = 700 torr
Temperature, T = 25°C, but K = 273 + °C
= 298 K
We are required to calculate the mass of Helium present in the flask.
We are going to use the ideal gas equation to first get the number of moles of He present in the flask.
Ideal gas equation, PV = nRT, where n is the number of moles and R is the ideal gas constant.
In this case, R will be 62.364 L.Torr/mol.K, since the pressure is in torr.
Rearranging the equation;
n = PV ÷ RT
= (0.25 L × 700 torr) ÷ (62.364 × 298 K)
= 0.00942 moles
With the number of moles, we can calculate the mass of He.
Mass = Number of moles × molar mass
Molar mass of He = 4.0 g/mol
Therefore,
Mass = 0.00942 moles × 4.0 g/mol
= 0.03768 g
= 0.038 g He
(Assume the balloon stretched very easily and the temperature was constant.)
Answer:
P₂ = 0.8 atm
Explanation:
Given data:
Initial pressure = 1 atm
Initial volume = 7 L
Final volume = 9 L
Final pressure = ?
Solution:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = Initial volume
P₂ = Final pressure
V₂ = Final volume
Now we will put the vales in formula.
P₁V₁ = P₂V₂
P₂ = P₁V₁ /V₂
P₂ = 1 atm × 7 L / 9 L
P₂ = 7 atm. L / 9 L
P₂ = 0.8 atm
B) without proper cooling the reactor will overheat
C) requires multiple different types of materials for the fuel rods
D) radiation can leak if not properly contained and cause death and destruction to nearby life