Answer:
D) It does not conduct electricity in any form.
Explanation:
Edge 2020 Trust
Answer:
E = 1.8 x 10⁵ J/mol
Explanation:
We are being asked the enery per mol for an emission line corresponding to 649 nm.
The energy of a photon is given by the porduct of Planck's contant times the frequency of the radiation,
E = hν
We also know that the frequency is given by
ν = c/λ
where c is the speed of light (3 x 10 ^8 m/s) and λ is 649 nm given in the problem. Therefore the energy per photon will be given by
E= hc/λ = 6.626 x 10⁻³⁴Js x 3 x 10 ^8 m/s/ 649 x 10 ⁻⁹ m
E = 3.1 x 10 ⁻¹⁹ J/ photon
(Note the wavelength has to be in nanometers (1nm= 10⁻⁹ m) and that the energy we get is the energy per a single photon. Thus we will need to multiply this result by Avogadro's number to answer this question.
E = 3.1 x 10 ⁻¹⁹ J/ photon x 6.022 x 10 ²³photon/mol
E = 1.8 x 10⁵ J/mol
The energy of the 649 nm emission from strontium ions in a flare is approximately 1.83 x 10⁵ Joules per mole. This calculation is done using the formula for energy of a photon and converting it to energy per mole using Avogadro's number.
The energy of a single photon can be calculated using the equation E=hc/λ, where h is Planck's constant (6.626 x 10⁻³⁴ J.s), c is the speed of light (3.00 x 10⁸ m/s), and λ is the wavelength of the light in meters. First, let's convert the wavelength from nanometers to meters, which results in 649 x 10⁻⁹ m.
Putting these values into the equation, we get E= (6.626 x 10⁻³⁴ J.s x 3.00 x 10⁸ m/s) / (649 x 10⁻⁹ m). The calculated value is about 3.05 x 10⁻¹⁹ J. However, the question asks for the energy in joules per mole. Multiplying this value by Avogadro's number (6.022 x 10²³ mol⁻¹), we get about 1.83 x 10⁵ J/mol.
Therefore, the energy of the 649 nm emission from strontium ions in a flare is approximately 1.83 x 10⁵ Joules per mole.
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B) This is a physical adaptation that helps a doe recognize her fawn.
C) The pattern of the speckled coat is used as a form of warning coloration.
D) The speckled coat blends with the light that filters through the forest leaves.
Answer:
The answer is D
Explanation: