Answer:
107 m
Explanation:
Convert km/h to m/s:
128.4 km/h × (1000 m / km) × (1 h / 3600 s) = 35.67 m/s
Distance = rate × time
d = 35.67 m/s × 3.0 s
d = 107 m
A pebble that sinks in water has greater density than a twig floats on top of the water. A pebble has more mass in it and more compact compared to a twig. The water cannot easily penetrate the pores of the pebble unlike twigs. That is why pebbles have greater densities than twigs.
Newton's 2nd Law of Motion: Force = (mass) · (acceleration)
Do I need to go any further ?
I get 575.25 Newtons .
Oh ! Look at that ! Right there at the top, it says "Using Newton's Second Law". This might have suggested to you that maybe you could solve the problem by using Newton's Second Law.
The time at which the current through the inductor reaches 63% of the maximum current is 4.85 s
The current is defined as the flow of the charge in the circuit is is the rate of flow of the charge.
At t=0 s there is no current in the circuit because the switch is not closed and the circuit is not complete. The current across the LR circuit increases exponentially, when the switch is closed, and becomes steady after a certain time.
Given that
The value of resistor is .120 ohm
The value of resistor is .330 ohm
The value of resistor is .240ohm
The value of the inductor is .1.6 mh
The voltage applied across the circuit is .9 V
To determine the value of effective resistance of this circuit we need to look at the circuit from inductor’s side i.e., from inductor’s side the resistors is connected in series with the parallel combination of resistors
The effective resistance of the circuit is:
…… (1)
Here, is the effective resistance of the circuit. Now substituting the values.
The current through the inductor is:
...... (2)
Here, is the current across the inductor, io is the maximum current in the circuit and L is the inductance across the inductor.
The current across the inductor is equal to the 63% of the maximum current in the circuit.
The current across the inductor is:
i=0.63io
Substitute 0.63io for 328 ohm , for 1.6 mH and for L in equation (2).
Simplify the above expression.
Taking natural log on both sides and simplify.
Thus, the time at which the current through the inductor reaches 63% of the maximum current is
To know more about current follow
The time at which the current through the inductor reaches 63% of the maximum current is or .
Further Explanation:
At there is no current in the circuit because the switch is not closed and the circuit is not complete. The current across the LR circuit increases exponentially, when switch is closed, and becomes steady after certain time.
Given:
The value of resistor is .
The value of resistor is .
The value of resistor is .
The value of the inductor is .
The voltage applied across the circuit is .
Concept:
To determine the value of effective resistance of this circuit we need to look at the circuit from inductor’s side i.e., from inductor’s side the resistors is connected in series with the parallel combination of resistors and .
The effective resistance of the circuit is:
…… (1)
Here, is the effective resistance of the circuit.
Substitute the for , for and for in equation (1).
The current through the inductor is:
...... (2)
Here, is the current across the inductor, is the maximum current in the circuit and is the inductance across the inductor.
The current across the inductor is equal to the 63% or times of the maximum current in the circuit.
The current across the inductor is:
Substitute for , for and for in equation (2).
Simplify the above expression.
Taking natural log on both sides and simplify.
Thus, the time at which the current through the inductor reaches 63% of the maximum current is or .
Learn more:
1. Conservation of energy brainly.com/question/3943029
2. Average translational energy brainly.com/question/9078768
3. The motion of a body under friction brainly.com/question/4033012
Answer Details:
Grade: Middle School
Subject: Physics
Chapter: Current Electricity
Keywords:
Resistor circuit, LR circuit, current, current across inductor, time constant, 4.85 microsecond, 4.85 microsec, 4.85 micros, 4.85*10-6 s, 4.85*10^6 s, 4.85*10-6 sec, 4.85*10^6 sec.