5 to 3 = blank to 6
Answer:
Congruent segments are simply line segments that are equal in length. Congruent means equal. Congruent line segments are usually indicated by drawing the same amount of little tic lines in the middle of the segments, perpendicular to the segments
Step-by-step explanation:
____ Set Up: 10(40) = x ∙ 50
____ Identify: Mrs. Gonzales’ time is unknown
____ Check: 10(40) = 8(50)
____ Solve: x = 8
____ Strategize: Let x = Mrs. Gonzales’ time
Gonzales took 8 minutes to type the same amount that Jones did in 10.
10x40=400. 400/50=8
The room is 4 yards. 12/3=4.
Please tell me if im wrong!
Approximate the solution to the equation f(x)=g(x) using three iterations of successive approximation. Use this graph as a starting point. (It’s not x= -7/8)
In the graphing tool, choose the custom option in the Relationship menu to graph the functions f(x) = x^3 + 3 and g(x) = x^2 + 2.
Adjust the zoom level of the graph so you can see the point where the two graphed functions intersect. Then, left-click on the point where the functions intersect. The values of the point you click on, rounded to the nearest hundredth, will appear for about 2 seconds.
Note: If you’re not using a mouse (or a mouse with left-click ability), perform the equivalent zoom-in action on your device to see the intersection point values rounded to the nearest hundredth.
Then, approximate (to the nearest hundredth) the solution of f(x) = g(x) from part A of this question.
15 points PLZZZZZ URGENTTT! Urgent maximum wait is 24 hours!
Answer:
(a) -3/4
(b) -0.75
(c) -0.75
Step-by-step explanation:
It's a bit hard to tell what constitutes an "iteration" when using the bisection method to approximate a polynomial root. For the purpose here, we'll say one iteration consists of ...
Thus, the result of the iteration consists of a bracketing interval and the choice of one of the interval's ends as the solution approximation.
__
(a) We observe that the graphs intersect in the interval (-1, 0). For the first iteration, we evaluate f(x)-g(x) at x=-1/2. This tells us the solution is in the interval (-1, -1/2). The x-value closest to the root is x=-1/2.
For the second iteration, we evaluate the function f(x)-g(x) at x=-3/4. This tells us the solution is in the interval (-1, -3/4). The x-value closest to the root is x=-3/4.
For the third iteration, we evaluate the function f(x)-g(x) at x=-7/8. This tells us the solution is in the interval (-7/8, -3/4). The x-value closest to the root is x=-3/4.
__
(b) The graph tells us the solution is approximately 0.7549. Rounded to 2 decimal places, the solution is approximately 0.75.
__
(c) The above solution found after 3 iterations rounded to 2 decimal places is exactly 0.75.
__
See the attached table for function values.
_____
Comment on bisection iteration
Since you cut the interval containing the root in half with each iteration, you gain approximately one decimal place for each 3 iterations. When the function value is very nearly zero at one of the interval endpoints, it can take many more iterations to achieve a better result.
Here, it takes 4 more iterations before an x-value becomes closer to the solution (x≈-97/128). And it takes one more iteration to move the end of the interval away from -3/4. After these 5 more iterations (8 total), the solution is known to lie in the interval (-97/128, -193/256). The corresponding solution approximation is -193/256. It is still only correct to 2 decimal places.
No 6.2 could be put as 6.20 and 1.75
6 is bigger than 1