The total number of legs , 1,500 , on four-legged and two-legged animals in a zoo can be represented by the equation 4x+2y=1,500. Interpret the x- and y- intercepts. Please show work so I can understand , if yu cant you can just give me the answers.
Answers
X
1) subtract 2y on each side => 4x = 1500 - 2y
2) divide by 4 => x = (1500-2y)/4
Y
1) subtract 4x on each side => 2y = 1500 - 4x
2) divide by 2 => y = (1500 - 4x)/2
Final answer:
The equation 4x + 2y = 1,500 refers to a zoo with two- and four-legged animals. The x-intercept at x = 375 represents the scenario with only four-legged animals, while y-intercept at y = 750 refers to the situation with only two-legged animals.
Explanation:
In the equation 4x + 2y = 1,500, 'x' stands for the number of four-legged animals and 'y' stands for the number of two-legged animals. The x-intercept is the value of 'x' when 'y' is zero, and the y-intercept is the value of 'y' when 'x' is zero. This can be calculated by setting the other variable to zero and solving for the remaining variable. For the x-intercept, when y=0, the equation becomes 4x = 1,500. Solving this gives x = 375. This implies that if there were no two-legged animals, there would be 375 four-legged animals. Similarly, for the y-intercept, when x=0, the equation becomes 2y = 1,500. Solving this gives y = 750, implying that if there were no four-legged animals, there would be 750 two-legged animals.
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Answer:
(12 2/3)/( 2 1/3)= 38/7 or 5 3/7 or 5.43 decimal
Step-by-step explanation:
Simplify the following:
(12 + 2/3)/(2 + 1/3)
Put 2 + 1/3 over the common denominator 3. 2 + 1/3 = (3×2)/3 + 1/3:
(12 + 2/3)/((3×2)/3 + 1/3)
3×2 = 6:
(12 + 2/3)/(6/3 + 1/3)
6/3 + 1/3 = (6 + 1)/3:
(12 + 2/3)/((6 + 1)/3)
6 + 1 = 7:
(12 + 2/3)/(7/3)
Put 12 + 2/3 over the common denominator 3. 12 + 2/3 = (3×12)/3 + 2/3:
((3×12)/3 + 2/3)/(7/3)
3×12 = 36:
(36/3 + 2/3)/(7/3)
36/3 + 2/3 = (36 + 2)/3:
((36 + 2)/3)/(7/3)
36 + 2 = 38:
(38/3)/(7/3)
Multiply the numerator by the reciprocal of the denominator, (38/3)/(7/3) = 38/3×3/7:
(38×3)/(3×7)
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Answer: 38/7
15,612 gallons
B.
17,110 gallons
C.
16,222 gallons
D.
15,112 gallons
Answers
Answer:
There are 15,112 gallons of water will remaining in the pool ⇒ answer D
Step-by-step explanation:
* Lets explain how to solve the problem
- The rate is the ratio between two related quantities in different units
- The pool is leaking slowly at rate 9 gallons per second that means the
quantity of the water in the pool decreased 9 gallons each day
- The find the remaining gallons in the pool after 111 days, find the
amount of water has leaked from the pool in these days
∵ The rate of leaking is 9 gallons per day
∵ Mike does not replace the water that has leaked from the pool
- The amount of water leaked in some days = the rate of leaking
× the number of days
∵ The number of days is 111 days
∵ The amount of water lacked = 9 × 111 = 999 gallons
∵ The amount of water remaining in the pool after some days =
the total amount in the pool - the amount of leaked in that days
∵ The pool holds 16,111 gallons of water
∴ The amount of water remaining = 16111 - 999 = 15112 gallons
* There are 15,112 gallons of water will remaining in the pool
Answers
Answer:
Prime factorization of 65 is
Solution:
Need to find the prime factorization of 65.
Prime factorization is finding all the prime factors of 65.
Method is to take prime number one by one . check whether the given number is divisible by the prime number till you get all the prime factors of given number.
In our case number is 65 . since given number 65 is not divisible by first two prime number that are 2 and 3 , divide 65 by third prime number = 5
That means 65 =
Now if you see, both factors that are 5 and 13 are prime numbers.
So prime factorization of 65 is
65 has factors of 5 and 13
5•13
Answers
Answer:
Step-by-step explanation: