An object, m=1.7 kg, is dropped from a ladder 2 m off the ground. What is the velocity of the object right before its hits the ground?

Answers

Answer 1

Answer: v^2 = u^2 + 2as
u=0 m/s
a=g=10 m/s^2
s=2 m

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If an astronaut weighs 750 N on the ground, what will he weigh in earth orbit 400 km above the earth’s surface? R_earth = 6.38 × 10^6 m,
m_earth=5.97×10^24 kg
G=6.674×10^−11 Nm^2/kg^2

Answers

Answer:

The weight of the astronaut in Earth's orbit 400 km above the Earth's surface is 664.115 N

Explanation:

The given parameters are;

The weight of the astronaut on the ground = 750 N

The height of the orbit above the Earths surface = 400 km

The radius of the Earth = 6.38 × 10⁶ m

The mass of the Earth = 5.97 × 10²⁴ kg

The universal gravitational constant G = 6.674 × 10⁻¹¹ Nm²/kg²

From Newton's law of universal gravitation, we have;

$Weight \ on \ ground \ of \ astronaut \ F_W =G* (M_(Earth) * m_(astronouat))/(R_(Earth)^(2)) = 750 \ N$

$F_W =6.674 * 10^(-11)* (5.97 * 10^(24)* m_(astronouat))/((6.38 * 10^6)^(2)) = 750 \ N$

$m_(astronaut)$ = ((6.38 × 10⁶)² × 750)/((6.674 × 10⁻¹¹) × (5.97 × 10²⁴)) ≈ 76.62 kg

The mass of the astronaut ≈ 76.62 kg

For the weight of the astronaut in Earth orbit 400 km (400 × 10³ m) above the Earth's surface, we have;

$F_(W \ in \ orbit) =6.674 * 10^(-11)* (5.97 * 10^(24)* 76.62)/((6.38 * 10^6 + 400 * 10^3)^(2) ) = 664.115 \ N$

The weight of the astronaut in Earth's orbit 400 km above the Earth's surface = 664.115 N.

53 yards per hour into inches per week

Answers

53 yards per houris a speed value and when converted gives 320544 inches per week.

What is speed value?

The speed value is defined by the distance traveled by the object with reference to the time. It is a scalar quantity, with a magnitude but no direction. The speed is calculated using the formula:

Speed = Distance ÷ Time

It can be measured in, meters per second, miles per hour, kilometers per hour, etc.

From the known data:
7 days per week
24 Hours per day
3 ft per yard
12 inches per feet

The conversion of yards per hour into inches per week is given as:

= 53 yards per hour × 3 feet per yard × 12 inches per foot × 24 hour per day × 7 day per week

= 53 × 3 × 12 × 24 × 7
= 320,544 inches per week

Therefore, the unit is converted and is 320,544 inches per week.

Learn more about speed, here:
brainly.com/question/10449029

#SPJ5

53 yards per hour would be 320544 inches per week :)

Hope this helps

A photon with a wavelength of 2.29 × 10^–7 meter strikes a mercury atom in the ground state.Calculate the energy, in joules, of this photon. [Show all work, including the equation and
substitution with units.]

Answers

Answer:

Energy of photon, $E=8.64* 10^(-19)\ J$

Explanation:

It is given that,

Wavelength of photon, $\lambda=2.29* 10^(-7)\ m$

It strikes a mercury atom in the ground state. We have to find the energy of this photon. It can be calculated using below relation as :

$E=(hc)/(\lambda)$

Where

h is the Planck's constant

c is the speed of light

So, $E=(6.6* 10^(-34)\ J-s* 3* 10^8\ m/s)/(2.29* 10^(-7)\ m)$

$E=8.64* 10^(-19)\ J$

Hence, the above value is the energy of this photon.

detailed solution is attached

Explain why plastic comb rubbed with wool attracts pieces of paper

Answers

Answer:

Static electricity

Explanation:

Opposite charges attract each other.

Which air pressure reading is likely an indicator of clear weather?a. 900 mb
b. 950 mb
c. 1000 mb
d. 1050 mb

Answers

1050 mb of air pressure is likely an indicator of clear weather. The correct option among all the options given in the question is option "d". In reality, higher pressure is mostly associated with clear and good weather while stormy or bad weather is often associated with low air pressure.

If a car goes along a straight road heading west and speeds up from 25 ft/s to 60 ft/s in 5 s, calculate the acceleration.

Answers

Acceleration =

   (change in speed) / (time for the change)
and
   direction of the change.

Change in speed = (end speed)-(start speed) = (60 - 25) = 35 f/s
Time for the change = 5 sec
Direction of the change = west

   Acceleration = 7 ft/sec² west .

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