Three weeks ago John bought stock at 491/4; today the stock is valued at 497/8. We could say the stock is performing at which of the following?A. Below par
B. Above par
C. On par
D. Par equality

Answers

Answer 1

Answer: Rate at which John bought the stocks 3 weeks ago = 491/4
Rate at which John sold the stock = 497/8
Amount of loss incurred by John = (497/8) - (491/4)
= (497 - 982)/8
= - (485/8)
From the above deduction it can be easily said that the stock is performing below par. The correct option among all the options that are given in the question is option "A".

Answer 2

Answer:

The Correct Answer Is B- Above Par

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Choose the graph of the function given below.f(x) = 2x+1

Answers

graph of the function

ABC is a straight angle.which equation can be used to find the measure of the unknown angle?

Answers

Answer:

140 x 180

Step-by-step explanation:

Final answer:

Explanation:

To find the measure of the unknown angle in a straight angle ABC, you can use the equation A = A + A. This equation is derived from the Pythagorean theorem, which relates the legs of a right triangle to the length of the hypotenuse. In a straight angle, the two legs are equal, so the equation simplifies to A = 2A. Therefore, the measure of the unknown angle is twice the measure of one of the legs

What is the algebraic expression for the following word phrase: the quotient of 3 and z

Answers

3/z
Or at least im quite sure, being that quotient implies division

3 divided by z is the answer

2) A student uses the substitution method to solve the system of equations below algebraically.x = 4y + 5
x = 3y - 2

Which equivalent equation could be used?
y = 3(4y + 5) - 2
x = 3(4y + 5) - 2
x = 4(3y - 2) + 5
4y + 5 = 3y - 2

Answers

Pretty sure it's the last one.

Can someone plz explain and gimme the answer...

Answers

Answer:

The choice two

$5 √(2)$

Step-by-step explanation:

${a}^(2) + {b}^(2) = {c}^(2) \n {5}^(2) + {5}^(2) = {c}^(2) \n 25 + 25 = {c}^(2) \n 50 = {c}^(2) \n c = 5 √(2)$

Find the equation of all tangent lines having slope of -1 that are tangent to the curve y=(9)/(x+1)

Answers

Answer: y = -x + 5 and y = -x - 7 (see attached graph)

Step-by-step explanation:

y = $(9)/(x + 1)$

= 9(x + 1)⁻¹

Use the product rule to find the derivative

a = 9 a' = 0

b = (x + 1)⁻¹ b' = -(x + 1)⁻²

ab' + a'b

= 9[-(x + 1)⁻²] + 0[(x + 1)⁻¹ ]

= $(-9)/((x + 1)^(2))$

Set the derivative equal to the desired slope of -1 to solve for x

-1 = $(-9)/((x + 1)^(2))$

-(x + 1)² = -9

(x + 1)² = 9

√(x + 1)² = √9

x + 1 = +/- 3

x + 1 = 3 x + 1 = -3

x = 2 x = -4

Plug those values into the original equation to solve for y:

y = $(9)/(x + 1)$

= $(9)/(2 + 1)$

= 3

(2, 3)

y = $(9)/(x + 1)$

= $(9)/(-4 + 1)$

= -3

(-4, -3)

Next, plug in the given slope (-1) and the coordinates above into the Point-Slope formula y - y₁ = m(x - x₁) to find the equations:

m = -1, (x₁ y₁) = (2, 3) m = -1, (x₁ y₁) = (-4, -3)

y - 3 = -1(x - 2) y + 3 = -1(x + 4)

y - 3 = -x + 2 y + 3 = -x - 4

y = -x + 5 y = -x - 7

Answer:

$f(x)=\frac9{x+1}\n f'(x)=-\frac9{(x+1)^2}\n f'(x)=-1\ \iff\ -\frac9{(x+1)^2}=-1\ \to \ \frac9{(x+1)^2}=1\ \to \ (x+1)^2=9\n |x+1|=3\ \to \ x+1=3\ \vee\ x+1=-3\n x_1=2\ \vee\ x_2=-4\n f(x_1)=f(2)=\frac9{2+1}=3\n f(x_2)=f(-4)=\frac9{-4+1}=-3$