inequality 4x − 25 < 125?
A. 2y6 + 4x2y2 + 10x + 12
B. 2y3 – 4xy2 – 3x + 12
C. 2y3 + 4xy2 + 10x + 9
D. 2y3 + 4xy2 + x + 12
Answer:
Therefore the distance across the patch of swamp water is 50 ft
Step-by-step explanation:
Given:
VW = 100 ft
WX = 60 ft
XZ = 30 ft
To Find:
ZY = l = ?
Solution:
In Δ VWX and Δ YZX
∠W ≅ ∠ Z …………..{measure of each angle is 90° given}
∠VXW ≅ ∠YXZ ..............{vertically opposite angles are equal}
Δ ABC ~ Δ DEC ….{Angle-Angle Similarity test}
If two triangles are similar then their sides are in proportion.
On substituting the given values we get
Therefore the distance across the patch of swamp water is 50 ft