Answer:
The best describes the process That adds a monosaccharide to an existing to an existing Polysaccaride.
Explanation:
Disaccharides are structure when two monosaccharides experience a parchedness reaction. They are held with each other by a covalent bond. we understand Sucrose is the most notable disaccharide, which is made out of the monomers glucose and fructose.
Monosaccharides encounter a parchedness reaction. They are held together by a covalent bond. Sucrose is the most notable disaccharide, which is made out of the monomers glucose and fructose.
Answer:
Individual organisms live together in an ecosystem and depend on one another. In fact, they have many different types of interactions with each other, and many of these interactions are critical for their survival.
amoeba
paramecium
euglena
Answer:
paramecium is the correct answer.
Explanation:
A common protozoan that moves by cilia is the paramecium.
paramecia are the single-celled organism, they live in the aquatic habitats.
The whole body of the protozoan is covered by cilia.
Cilia is hair-like organelles that help the paramecium to swim in the water as they have streamlined structure.
The function of cilia in the life cycle of a protozoan is it help in locomotion and in food ingestion.
phenotypes are expected in the offspring of this cross?
From a cross of homozygous dominant and homozygous recessive parent lines with heterozygous parents, a 1:1 phenotypic ratio is seen. Two types of phenotypes will form.
A dihybrid cross involves two traits. Example: an animal with both genes for height and body coloration is taken . The height is represented as T. T is for tall characters, and t is for short characters. A homozygous dominant character is represented as TT. Homozygous recessiveness is expressed by tt.
Another gene such as body coloration is taken. Black (B) is dominant over white (b). An animal with homozygous dominant is BB. An animal having homozygous recessive is bb.
A parent with homozygous dominant for tall character and homozygous recessive for body colour is represented by TTbb. An animal that is heterozygous for height and body coloration is taken as TtBb.
From the crossing, two phenotypes are derived, such as tall black and tall white. Out of all eight individuals, four are tall black and four are tall white. The phenotypic ratio is 1:1. The cross is explained below.
Hence, two types of phenotypes will be formed with a phenotypic ratio of 1:1.
To learn more about dihybrid crosses, refer to the following link
#SPJ2
the cross is AAbb*AaBb
There would be 4 different genotypes and 2 different PHENOTYPES for the offspring. (From the first gene we can get AA or Aa from the second one Bb or bb)
AAbb
Aabb have the same phenotype
AABb
AaBb have the same phenotype