1. n-3 104, d-16 =-5
1. n-3 104, d-16 =-5 - 1

Answers

Answer 1
Answer: is that the full question?then
n = 13 and d = 11

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I will give you brainliest!!! Solve the system of equations by graphing both equations with a pencil and paper y=x-3 y=-x+1

If x = −3, which number line shows the value of |x|?

Answers

The value of the absolute expression |x| at x = - 3 will be 3.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

The expression is given below.

⇒ |x|

If x = - 3, then the value of the expression will be given as,

⇒ |-3|

The value of the absolute function is always positive. Then the value of the expression is given as,

⇒ |-3|

⇒ 3

The value of the absolute expression |x| at x = - 3 will be 3.

More about the Algebra link is given below.

brainly.com/question/953809

#SPJ3

Answer:

answer is number three

Step-by-step explanation:

Hope this helps!

What is the quotient of −42 and −6?

Answers

Answer:

7

Step-by-step explanation:

Two negatives cancel out, so you divide just like normal 42÷6 is 7

The quotient is 7 (not negative as two negative numbers will cancel)

Evaluate -4 - 5 + 4 + (-5)

Answers

Answer:

-10

Step-by-step explanation:

Answer:

-10

Step-by-step explanation:

it just works

Susan averages 8 birdies in an 18 hole round of golf. how many birdies should she expect after playing 45?

Answers

Hey there, 8 birdies in an 18 hole is 8/18, 8/18 simplified is 4/9, 4/9*45=20. Therefore, the answer is 20 birdies.

How can 11,14,13 and 19 equal to 4

Answers

19 - 13 = 6
6 + 11 = 17
17 - 13 = 4

if the equation is h= -2x^2 + 12x -10

how do I find the max height?

Answers

One other way to solve this question is finding the derivative

h=-2x^2+12x-10

h'=-4x+12

now we have to find when this function will be zero

-4x+12=0

\boxed{\boxed{x=3}}

now we just replace this value at our initial function

h=-2x^2+12x-10

h_(max)=-2*(3)^2+12*3-10

h_(max)=-18+36-10

\boxed{\boxed{h_(max)=8}}
The maximum height is the ordinate value of the vertex of the parabola, ie: yV

Calculating yV:

y_V=(-\Delta)/(4a)\n \n y_V=-[(12^2-4*(-2)*(-10)])/(4*(-2))=(-(144-80))/(-8)=(-64)/(-8)=8