Lynn paid $12.21 for ribbon. The cost per yard was $1.48.How many yards of ribbon did Lynn buy?
Answers
Answer: Lyn bought 8.25 yards of ribbon.
Step-by-step explanation:
Given : Lynn paid $12.21 for ribbon.
The cost of ribbon per yard was $1.48.
Then by using division operation , the length of ribbon ( in yards) bought by Lyn is give by :-
Hence, the length of ribbon bought by Lyn =8.25 yards
i.e. Lyn bought 8.25 yards of ribbon.
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Answers
The simplest form of 1.6 is 5/8
What is simplest form ?
In mathematics, the simplest form is the fraction that has the smallest equivalent value.
Here, the given decimal number is 1.6 :
and to find its simplest form we put the same number of zeros as the numbers after decimal in the given number that is one zeros :
1.6 = 16/10
Now, dividing it by common factor that is 2 :
16/10 = 8/5
Therefore, the simplest form of 1.6 is 5/8
Learn more about fractions on:
#SPJ2
so 1.6 in simplest form is 1 3/5
Hope this helps! :D
Answers
Answers
Answer:
82,350
Step-by-step explanation:
8.235 x 10 ^4 = 82350
Answer:
0.0008235
Step-by-step explanation:
Convert the scientific notation to a decimal
Answers
47 minus 3 times the difference of 15 and 2
47-3(15-2)
Now we have to take the order of operations into consideration.
Parenthesis
Exponents
Multiplication/Division
Addition/Subtraction
Lets clear out the parenthesis.
47-3(15-2)
47-3(13)=47-39=8
Therefore, the final answer is 8
Answer:
Step-by-step explanation:
47 minus 3 times the difference of 15 and 2:
47 - 3(15-2) = 47 - 3(13) =47 - 39 = 8
VS
47 minus 3, times the difference of 15 and 2:
(47-3) (15-2) = (44)(13) = 572
Answers
Answer:
20
Step-by-step explanation:
let the number of rounds of golf played for the cost to equal be x.
-It costs $35/ round when the membership of $500 is paid, hence, total annual cost is:
#When membership is not paid, the annual cost is expressed as:
#Since the cost should be equal after x rounds, we equate the two to solve for x:
Hence, Mr Bailey has to play 20 rounds of golf for the cost in both scenarios to be equal.