they have the same number of protons
their charges are of the same signs
they have the same number of electrons
2. Batteries typically have
two positive terminals
two negative terminals one positive and one negative terminal
no terminals
1. when their charges are of the same signs
Explanation:
Electrostatic force is the force exerted betwen objects that have charge. The magnitude of the force is given by:
where k is the Coulomb constant, q1 and q2 are the charges of the two objects, and r is the separation between the two objects. The sign (and therefore the direction) of the force depends on the relative signs of the two charges. In fact:
- When the two charges have same sign, the force is positive, which means that it is a repulsive force
- When the two charges have opposite sign, the force is negative, which means that it is an attractive force
So, we can conclude that
Two charged objects repel each other when their charges are of the same signs
2. Two terminals, one positive and negative
Explanation:
Batteries are devices which provides (usually through some chemical reactions) a potential difference, also called electromotive force. When connected to a closed circuit, this potential difference provided by the battery "pushes" electrons through the circuit, generating an electric current.
Batteries have generally two terminals: one terminal at positive voltage, called positive terminal, and one terminal at negative voltage, called negative terminal. When connected to the circuit, electrons are pushed from the negative terminal through the circuit towards the positive terminal of the battery.
10 m/s, northwest
14 m/s, northwest
48 m/s, northwest
The correct answer to the question is : 10 m/s , northwest.
EXPLANATION:
As per the question, the velocity of wind V = 8 m/s towards north.
The velocity of the paper airplane is V' = 6 m/s towards west.
We are asked to calculate the actual velocity of the airplane.
By putting Pythagorean theorem, the actual velocity of the airplane is calculated as -
⇒
⇒
⇒
⇒ towards northeast.
Hence, the correct answer is 10 m/s , northwest.
What will that action cause her body to do? Why?
Which of Newton’s Laws applies to this situation?
Write a paragraph which incorporates all of the above information.
Answer:
In order to get back to the ship, the astronaut must throw the belt in the opposite direction the spaceship.
From Newton's third law of motion:
For every action, there is equal and opposite reaction.
In order to throw the belt away, astronaut would apply some force which cause same amount of force acting on her body in the opposite direction which would take her towards the spaceship.
Potential energy or stored energy, and kinetic energy, the energy due to motion can be balanced in the process of converting kinetic energy to potential energy during an uphill motion
The correct option for, which situation shows potential energy and kinetic energy are balanced is option;
A roller coaster car going uphill
The reason the selected option is correct is as follows:
Potential energy is the energy that is due to the relative position of an item in relation to a ground or zero state. The formula for potential energy due to the elevation is given as follows;
Potential energy, P.E. = m·g·h
Kinetic energy is the energy that is due to motion. The kinetic energy of an item is given as follows;
Kinetic energy, K.E. = (1/2) × m × v²
The potential and kinetic energy of a body is balanced when we have;
P.E. = m·g·h = K.E. = (1/2)·m·v²
Which gives;
g·h = (1/2)·v²
Therefore, a point is reached as the an body moves up a heal, where the potential energy (the energy due to height of the object) and the kinetic energy (the energy due to current speed) of the object are equal
The correct situation which shows potential energy and kinetic energy are balanced is therefore; A roller coaster car going uphill
Learn more about potential and kinetic energy here:
2.Reducing the friction between the wagon wheels
3.Reducing the length of the wagon handle
4.Increasing the friction between the wagon wheels
Answer:
2.Reducing the friction between the wagon wheels
Explanation:
If the friction between the wagon wheels and the rail is reduced, then less force will be needed to pull the wagon up. This is because the friction force goes in the opposite direction of the movement, that is, friction force opposes the desired movement, making it more difficult.
Answer:
No, the apple will reach 4.20041 m below the tree house.
Explanation:
t = Time taken
u = Initial velocity = 2.8 m/s
v = Final velocity = 0
s = Displacement
g = Acceleration due to gravity = -9.81 m/s² = a (negative as it is going up)
Equation of motion
The height to which the apple above the point of release will reach is 0.39959 m
From the ground the distance will be 1.3+0.39959 = 1.69959 m
Distance from the tree house = 5.9-1.69959 = 4.20041 m
No, the apple will reach 4.20041 m below the tree house.
The values in the option do not reflect the answer.
The apple will not reach the friend in the tree house as it will only reach a height of approximately 1.527 m.
To determine whether the apple will reach a friend in a tree house 5.9 m above the ground, we can use the equations of motion. Since the apple is thrown vertically upward, it will experience a negative acceleration due to gravity. Using the equation h = vo*t + (1/2)*a*t^2, where h is the final height, vo is the initial velocity, a is the acceleration, and t is the time, we can calculate the time it takes for the apple to reach a height of 5.9 m. Plugging in the values, we get:
5.9 = 2.8*t + (1/2)*(-9.81)*t^2
Simplifying the equation, we have:
-4.905*t^2 + 2.8*t - 5.9 = 0
Using the quadratic formula, we can solve for t. The quadratic formula is t = (-b ± sqrt(b^2 - 4ac)) / (2a), where a = -4.905, b = 2.8, and c = -5.9.
Plugging in the values, we get:
t = (-2.8 ± sqrt(2.8^2 - 4*(-4.905)*(-5.9))) / (2*(-4.905))
After evaluating the formula, we find that the apple will take approximately 1.527 seconds to reach a height of 5.9 m. Since the apple continues to rise after reaching this height, it will not reach the friend in the tree house.