The perimeter of a rectangle is twice the sum of its length and it’s width . The perimeter is 22 meters and I it’s length is 2 meters more then twice it’s width. What’s its length?
Answers
Answer:
The length of this rectangle is 8m.
Step-by-step explanation:
The problem states that the perimeter of a rectangle is twice the sum of its length and it’s width. So
The problem also states that the perimeter is 22 meters. So:
.
Also, it states that I is the length and it is 2 meters more then twice it’s width. So
What’s its length?
The width is 3m. The length is in function of the width, so:
The length of this rectangle is 8m.
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Answers
Answer:
y = -3x-5
Step-by-step explanation:
of the expression?
21.3 + (-34.87)
Answers
Answer:
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Step-by-step explanation:
21.3 + (-34.87) = -13.57
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Answers
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Step-by-step explanation:
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Answers
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Answers
Answer:
C= -145, (35/4, 295/8, 45)
Step-by-step explanation:
Use Gaussian elimination to find the values of x, y and z
Eq 1: -x+2y-z=20
Eq 2: x-2y+2z=25
Eq 3: 2x+4y-3z=30
- Multily Eq1 by 1 and add to Eq 2
Eq 1: (-x+2y-z=20 ) × 1
Eq 2: x-2y+2z=25
Eq 3: 2x+4y-3z=30
⇒ Eq1: -x+2y-z=20
Eq2: z= 45
Eq 3: 2x+4y-3z=30
- Multiply Eq 1 by 2 and then add to Eq 3
Eq1: (-x+2y-z=20 ) × 2
Eq2: z= 45
Eq3: 2x+4y-3z=30
⇒ Eq1: -x+2y-z=20
Eq2: z= 45
Eq3: 8y-5z= 70
- swap Eq 2 and Eq 3
Eq 1: -x+2y-z=20
Eq 3: 8y-5z= 70
Eq 2: z= 45
- Solve Eq 2 for z
Z=45
- solve Eq Eq 3 for y.
y= 295/8
- Using the value z=45 and y= 295/8, substitue in Eq 1 to get value of x
x= 35/4
- Substitue values of x,y and z in C= -3x-2y-z to get minimum value of C
C= -145
Answers
It is convenient to start with the 2-point form of the equation for a line.
... y - y1 = (y2 - y1)/(x2 - x1)×(x - x1)
Either point can be (x1, y1), and the other can be (x2, y2). If we take them in order, we get
... y - 4 = (16 - 4)/(5 - 3)×(x - 3) . . . . . fill in the two points
... y = 12/2(x -3) +4 . . . . . . . . . . . . . . add 4, simpliffy a bit
... y = 6x -18 +4 . . . . . . . . . . . . . . . . . eliminate parentheses
... y = 6x -14 . . . . . . . . . . . . . . . . . . . . put in slope-intercept form