When a can is crushed did it undergo a physical change

Answers

Answer 1

Answer: because even though the object got crush and misshape it still has the same identity. the identity never change

Related Questions

Consider a portion of a cell membrane that has a thickness of 7.50 nm and 1.4 µm ✕ 1.4 µm in area. A measurement of the potential difference across the inner and outer surfaces of the membrane gives a reading of 86.0 mV.a) Determine the amount of current that flows through this portion of the membraneb) By what factor does the current change if the side dimensions of the membrane portion is halved? The other values do no change increase by factor of 2decrease by factor of 8 decrease by factor of 2 decrease by a factor of 4 increase by factor of 4
Advantages and disadvantages of resonance
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Atoms become charged by gaining or losing _____. electrons protons neutrons

When magnesium (Mg2+) and fluorine (F1-) combine in an ionic bond, the resulting formula will be A) Mg2F.

B) Mg2F2.

C) MgF.

D) MgF2.

Answers

Answer is: D) MgF₂.

Magnesium fluoride is salt, ionic compound.

1) Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).

Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.

Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.

2) Fluorine (F) is nonmetal with greatest electronegativity, which meand it easily gain electrons.

Fluorine jas atomic number 9, which means it has 9 protons and 9 electrons. It gain one electron to form fluorine anion (F⁻) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.

Electron configuration of fluorine ion: ₉F⁻ 1s² 2s² 2p⁶.

The fluorine has one spare electron per atom and the magnesium has a need for 2. This means for one magnesium you need two fluorine atoms making the formula MgF2.

In the mobile m1=0.42 kg and m2=0.47 kg. What must the unknown distance to the nearest tenth of a cm be if the masses are to be balanced? The answer is 13.4 In the mobile what is the value for m3 to the nearest hundredth of a kilogram?

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From he question we are told that

The first mass is $m_1 = 0.42kg$

The second mass is $m_2 = 0.47kg$

From the question we can see that at equilibrium the moment about the point where the string holding the bar (where $m_1 \ and \ m_2$ are hanged ) is attached is zero

Therefore we can say that

$m_1 * 15cm = m_2 * xcm$

Making x the subject of the formula

$x = (m_1 * 15)/(m_2)$

$= (0.42 * 15)/(0.47)$

$x = 13.4 cm$

Looking at the diagram we can see that the tension T on the string holding the bar where $m_1 \ and \ m_2$ are hanged is as a result of the masses ( $m_1 + m_2$ )

Also at equilibrium the moment about the point where the string holding the bar (where ( $m_1 +m_2$ ) and $m_3$ are hanged ) is attached is zero

So basically

$(m_1 + m_2 ) * 20 = m_3 * 30$

$(0.42 + 0.47) * 20 = 30 * m_3$

Making $m_3$ subject

$m_3 = ((0.42 + 0.47) * 20 )/(30 )$

$m_3 = 0.59 kg$

Who was the man who lived from 460B.C.–370B.C. and was among the first to suggest the idea of atoms?a. Atomos
c. Democritus
b. Dalton
d. Thomson Please select the best answer from the choices provided A B C D

Answers

c. Democritus was a Greek philosopher who defined the concept of atoms and is the only one of the answer choices who lived during that time period.

A mass that weighs 8 lb stretches a spring 24 in. The system is acted on by an external force of 4 sin 4t lb. If the mass is pulled down 6 in. and then released, determine the position of the mass at any time. Determine the first four times at which the velocity of the mass is zero

Answers

Answer:

$t = (\pi)/(8), (\pi)/(4), (3\pi)/(8), (3 \pi)/(4)$

Explanation:

The equation of force is

F = 4 sin 4 t

Compare with the standard equation

f = A sin wt

where, w is the angular frequency and A is the amplitude.

Now

w = 4 rad/s

Let the time period is T.

the relation for the time period is

$T = (2\pi)/(w)\n\nT = (2 \pi)/(4)\n\nT = (\pi)/(2)$

the time period is defined as the time taken by the body to complete one oscillation.

So, the velocity is zero at the extreme points where the object is at time, T/4 and its odd T/2, 3T/4, 3T/2, etc.

So, the velocity is zero at time

$t = (\pi)/(8), (\pi)/(4), (3\pi)/(8), (3 \pi)/(4)$

Final answer:

To determine the position of the mass and the times when the velocity is zero in a mass-spring system.

Explanation:

To determine the position of the mass at any time, we need to solve the equation of motion for the mass-spring system. The equation is:

mx'' + kx = Fext

where m is the mass, x is the displacement of the mass from its equilibrium position, k is the spring constant, and Fext is the external force. We can solve this differential equation to find the position of the mass as a function of time.

To determine the first four times at which the velocity of the mass is zero, we need to solve for the velocity of the mass, which is given by:

v = x'

We can find the times at which the velocity is zero by finding the values of t for which x' = 0.

Learn more about Mass-spring system here:

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A car travels 15 kilometers west in 10 minutes. After reaching the destination, the car travels back to the starting point, again taking 5 minutes. What is the average velocity of the car?A. 0 meters/seconds
B. 1.0 meters/seconds
C. 1.5 meters/seconds
D. 2.0 meters/seconds

Answers

Speed = (distance traveled) / (time to travel the distance).

Strange as it may seem, 'velocity' is completely different.

Velocity doesn't involve the total distance traveled at all.
Instead, 'velocity' is based on 'displacement' ... the distance
between the start-point and end-point, regardless of the route
taken to get there. So the displacement in driving once around
any closed path is zero, because you end up where you started.

Velocity =

   (displacement during some time)
divided by
      (time for the displacement)

AND the direction from the start-point to the end-point.

For the guy who drove 15 km to his destination in 10 min, and then
back to his starting point in 5 min, (assuming he returned by way of
the same 15-km route):

   Speed = (15km + 15km) / (10min + 5min) = (30/15) (km/min)

   = 2 km/min.

Velocity = (end location - start position) / (15 min) = Zero .

An unknown fiber sample is found at a crime scene. Forensic scientists measure its index of refraction and obtain a value of 1.48. A suspect's jacket was made of Dacron polyester, his jeans were made of cotton, his shirt was made of rayon, and his tie was made of acetate. Which piece of clothing may match the fiber at the crime scene?Question 12 options:

tie

shirt

jeans

jacket

Answers

The closest refractive index to the one observed is that of rayon, about 1.51. Therefore, the fiber is likely from the suspect's shirt.

Answer:

shirt

Explanation:

shirt

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