There were 3,905 more hits on the school website in January than February. February had 9,854 hits. About how many hits did the website have during January and February?

Answers

Answer 1

Answer: 9,854
-
3,905
_____
5,949

Answer 2

Answer: It is actually 5,940 because the equation asked about how many hits did the website have. Therefore, you have to round.

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Help ASAPMr. Anthony wants to know how some student athletes are improving in the number of push-ups they can do. These dot plots show the number of push-ups each student was able to do last month and this month. (file attached has an image of dot plots)

What is the increase in the mean number of push-ups from last month to this month?
Please explain what you did and how you did it.

Answers

Increase number in the mean number of push-ups from last month to this month is,

⇒ 7.5

What is mean by Subtraction?

Subtraction in mathematics means that is taking something away from a group or number of objects. When you subtract, what is left in the group becomes less.

Given that;

Mr. Anthony wants to know how some student athletes are improving in the number of push-ups they can do.

Hence, Mean of number of push-ups last month is,

⇒ 10 × 2 + 15 × 2 + 25 × 3 + 35 × 1 / 8

⇒ 160 / 8

⇒ 20

And, Mean of number of push-ups this month is,

⇒ 10 × 1 + 15 × 1 + 25 × 1 + 30 × 3 + 40 × 2 / 8

⇒ 220 / 8

⇒ 27.5

Hence, Increase number in the mean number of push-ups from last month to this month is,

⇒ 27.5 - 20

⇒ 7.5

Learn more about the subtraction visit:

brainly.com/question/17301989

#SPJ3

Another way to say "mean" is average. To find the average you would add all the numbers together and then divide by how many addends you had. So to find last month you would add all the dots together giving you 160. Divide by 8 (the number of dots) and you get 20. To find this month do the same thing and you end up with 220/8 which gives you 27.5. So the difference between last month and this month (27.5-20) is 7.5 :)

The side lengths of the figure below are given in centimeters.If the perimeter of this figure is 78 cm, what is the value of x?

Answers

Answer:

x=-12 or 6

lol this was so long ago.

this is elemantry but the answer comes out radical. what?,,,

Please help. Full explanation if you can.1. The ratio of boots to sandals in a shoe store is 8:3. If there are 245 more boots than sandals in the store, how many boots are there??

Answers

392 boots. If you divide everything into "sets" of an unknown amount, there are 5 more "sets" of boots than sandals, also known as the 245 boots. So if you divide 245 by 5, you'll get the number of items in a "set". Then just multiply by 8 from the 8:3 ratio. If you check it, it will come out to 392 boots to 147 sandals, which I think is ridiculous since sandals are supposed to come in pairs so you should never have a odd number. But anyway, 392 - 147 = 245

Given f(x) = e^x and g(x) = x – 2, what is the range of (g*f)(x)

Answers

For this case we have the following functions:

$f (x) = e ^ x\ng (x) = x-2$

By definition we have to:

$(f * g) (x) = f (x) * g (x)$

Substituting:

$(f * g) (x) = e ^ x (x-2)$

The range of the function is given by all values of "and" valid. That is, all the real numbers.

ANswer:

(-∞,∞)

Graphic attached

~~~20 POINTS~~~
Please answer these two math questions for me :)

Answers

Foreword

"Please tell Kat that Brainly gives half the points she selects to each user that answers the question."

The Answers

#1:
We are trying to find the MAD for each set of the teachers' grades. To find the MAD (again) find the mean of the teachers' grades. Then, take each of the teachers' grades and find the absolute value of the difference between that grade and the mean grade. Add the differences up, and divide the result by the number of teachers (10).

Do the first table first (first things first!). Find the mean by adding up the grades and dividing them by the number of teachers (10).

76 + 81 + 85 + 79 + 89 + 86 + 84 + 80 + 88 + 79 = 827
827/10 = 82.7

The mean grade for the first table is 82.7.

Now, we need to find the absolute value of the difference between each of the teachers' grades and the mean.

82.7 - 76 = 6.7

82.7 - 81 = 1.7

85 - 82.7 = 2.3

82.7 - 79 = 3.7

89 - 82.7 = 6.3

86 - 82.7 = 3.3

84 - 82.7 = 1.3

82.7 - 80 = 2.7

88 - 82.7 = 5.3

82.7 - 79 = 3.7

Now, we need to add up the result.
6.7 + 1.7 + 2.3 + 3.7 + 6.3 + 3.3 + 1.3 + 2.7 + 5.3 + 3.7 = 37

Now, we divide the result by the number of teachers.
37/10 = 3.7

So the MAD for the first table is 3.7.

Now we do the same thing for the second table.

$Mean= (sum\ of\ grades)/(10)$

79 + 82 + 84 + 81 + 77 + 85 + 82 + 80 + 78 + 83 = 811
811/10 = 81.1

Bad grades.

$MAD= (absolute\ value\ of\ difference\ of\ each\ grade\ from\ the\ mean)/(10)$

81.1 - 79 = 2.1

82 - 81.1 = 0.9

84 - 81.1 = 2.9

81.1 - 81 = 0.1

81.1 - 77 = 4.1

85 - 81.1 = 3.9

82 - 81.1 = 0.9

81.1 - 80 = 1.1

81.1 - 78 = 3.1

83 - 81.1 = 1.9

Add.
2.1 + 0.9 + 2.9 + 0.1 + 4.1 + 3.9 + 0.9 + 1.1 + 3.1 + 1.9 = 21
21/10=2.1

Now, we compare the MAD's. If the MAD for the second table is greater than the MAD for the first table, then the teachers have not improved/were sleeping. If not, then the teachers have improved/got lucky.

$MAD_(1st\ table)=3.7$

$MAD_(2nd\ table)=2.1$

Hooray! They improved/got lucky, by 1.6 points to be precise.

#2:
Remember from the previous answer I gave (the other question you asked) the example with a MAD of 0? That's because they were all exactly on the mean (4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 = 40, 40/10 = 4, MAD = 0). Therefore, if the MAD of the teachers' grades was zero, that means they all got the same score! Hooray! Mission accomplished. Or the common core machine has succeeded in producing identical copies of teachers.

Backword

I hope you know what the MAD is now.

Given f (x) and g(x)+k look at the graph below and determine the value of K

Answers

Answer:

k=5

Step-by-step explanation:

Let's find the equation for both lines. For the line in blue we know that passes through points (0,-2) and (3,-1) with this information we can use the formula of the line:

$y-y_1=(y_2-y_1)/(x_2-x_1) (x-x_1)$