Drug medication are often prescribed on the basis of body mass. The adult dosage of Elixophyllin, a drug used to treat asthma, is 6 mg/kg of body mass. Calculate the dose in milligrams for a 160 lb person.

Answers

Answer 1
Answer:

Answer:

The dose of Elixophyllin for a person of 160 lb is 436.36 mg.

Explanation:

First you have to go from pounds to kilograms.  160 lb x 1kg/2.2lb = 72.73 kg.

Then you have to multiply the dosage by the body mass in kilograms.

(6 mg/kg) x 72.73 kg ⇒ 436.36 mg.


Related Questions

Choose the correct coefficients to balance the following equation: __Zn + __HCl Imported Asset __ZnCl2 + __H2.1, 2, 2, 21, 2, 1, 12, 4, 2, 20, 2, 0, 0
Calculate the mass in grams of 5.0 moles of Li
The addition of heat energy to a system always causes the temperature of that system to increase. True False
In a given chemical reaction, the energy of the products is less than the energy of the reactants. Which statement is true for this chemical reaction?
the relative molecular mass of sodium hydroxide is 40. if 60 grams of sodium hydroxide are dissolved in water how many moles will there be in the solution?

Which part of the human ear is part of the inner ear? A)cochlea
B)oval window
C)ear canal
D)Hammer

Answers

Cochlea is present in inner ear !!

So go with A !!
if you need more info on that ; comment !!

Answer: cochlea


The cochlea is responsible for turning sound waves which is what makes you hear.

This reaction is an explosive reaction of a strong acid combining with a strong base.H2SO4 + 2NaOH → 2H2O + Na2SO4

Which compounds are the reactants and which are the products?

A.
reactants: H2SO4 + 2NaOH
products: 2H2O + Na2SO4

B.
reactants: 2NaOH + Na2SO4
products: H2SO4 + 2H2O

C.
reactants: 2H2O + Na2SO4
products: H2SO4 + 2NaOH

D.
reactants: H2SO4 + 2H2O
products: 2NaOH + Na2SO4

Answers

A) reactants: H2SO4 + 2NaOH and products: 2H2O + Na2SO4
The reactants are found on the left side of the equation, before the arrow.
The products are found on the right side of the equation, after the arrow.

Answer:

A. Reactants: H2SO4 + 2NaOH

products: 2H2O + Na2SO4

Explanation:

What is a good way to study

Answers

Answer:

focus in class and take your time on work and get good grades

Explanation:you can do better when you understand what you are doing/learning

Which is a binary ionic compound?

Answers

there is no choices but A binary compound is a compound composed of only two elements. Binary compounds composed of a metal and a non metal and are named as ionic compounds.

Lithium fluoride  LiF  

Lithium chloride  LiCl  

Lithium phosphide  Li3P  

Beryllium fluoride  BeF2  

Beryllium chloride BeCl2  

Beryllium bromide BeBr2  

Beryllium iodide BeI2  

Beryllium phosphide Be3P2

Boron fluoride  BF3  

Boron chloride BCl3

hope this helped :) pls give branliest

A binary ionic compound is composed of ions of two different elements - one of which is a metal, and the other a nonmetal.

The development of nuclear power has provided electricity for less money, but at a cost. What may be considered a "cost" of nuclear power? A. Large amounts of energy are produced very cheaply.

B.
It takes a lot of energy to run a nuclear power plant.

C.
Nuclear power plants provide new jobs for a community.

D.
The radioactive waste is unsafe and hard to store safely.

Answers

D. A disadvantage of nuclear power is that waste products are unsafe and hard to store. They must be stored for many hundreds of years before they becomes safe and easier to dispose of, and we currently don't have a good method of storing them in the meantime.


d. radioactive waste is extremely unsafe and difficult to store safely.

What is the pOH of a 4.8x10^-10M H+ solution

Answers

Answer : The value of pOH of the solution is, 4.68

Explanation : Given,

Concentration of H^+ ion = 4.8* 10^(-10)M

As we know that the pH is the negative logarithm of hydrogen ion concentration.

Mathematical representation is :

pH=-\log [H^+]

First we have to calculate the pH of the solution.

pH=-\log [H^+]

pH=-\log (4.8* 10^(-10))

pH=9.32

Now we have to calculate the pOH.

pH+pOH=14\n\npOH=14-pH\n\npOH=14-9.32=4.68

Therefore, the value of pOH of the solution is, 4.68

pH is 9.32 based on the [H+]. we know that:    14=pH+pOH so   pOH would be:   pOH=4.68