PHYSICS MIDDLE SCHOOL

Jacob has a bucket of ice. He covers the bucket with a lid and sets it in the sun. The ice melts into liquid water. How does the mass of the ice compare with the mass of the water? A. The mass of the ice is the same as the mass of the water. B. The mass of the ice is more than the mass of the water. C. The mass of the ice is less than the mass of the water. D. There is no way to determine this from the information given.

Answers

Answer 1

Answer:

Answer:

Explanation:

According to law of conservation of energy:

Mass (or energy) can neither be created nor destroyed but they can be changed into different forms.

As there is a lid on the bucket there is no evaporation happening, hence the mass will remain same.

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Which way does the friction arrow in an FBD for a moving object point?in the direction of motion

opposite to the net force

left

opposite to motion

Answers

The friction arrow in an FBD for a moving object point is in opposite way to motion. Because friction always works in the opposite direction of the motion of the object.

Answer: Option D

Explanation:

When two object come into contact, the contact force come into play. Now, one component of the contact force i.e. the normal forces act perpendicularly at the direction of motion. Whereas, the frictional forces always acts parallel at the direction of the force acting on the object but in the opposite way.

For example, if we slide a book on the table to the right hand side, the exact equal and opposite frictional force will induce in the opposite direction, tempting to reduce the motion.

At which point will the riders experience centripetal acceleration?

Answers

the answer would be (X)

A book with a mass of 5 kg is pushed off a table with the velocity of 2 m/s. What is its momentum? A. 7 kg-m/s
B. 3 kg-m/s
C. 15 kg-m/s
D. 10 kg-m/s

Answers

The momentum of a book with a mass of 5 kg is pushed off a table with a velocity of 2 m/s is option D. 10 kg-m/s.

What is momentum?

Momentum is the quantity of motion of a moving body, measured as a product of its mass and velocity.
It is the vector quantity. It has both magnitude and direction.
In the International System of Units, the unit of measurement of momentum is Kg*m/s.

What is the momentum of a book with a mass of 5 kg is pushed off a table with a velocity of 2 m/s?

Formula of momentum = p = mv

Here,

p = momentum

m = mass

v = velocity

Here the given mass is 5 and velocity is 2. then,

p = mv

=5×2

=10 Kg*m/s

Hence, the momentum of a book with a mass of 5 kg is pushed off a table with a velocity of 2 m/s is option D. 10 kg-m/s.

To learn more about momentum, refer to: brainly.com/question/26138070

#SPJ2

Momentum=Mass•Velocity

=5 kg•2 m/s

=10 kg-m/s

A(n)___ uses sunlight to produce oxygen and food in a plant cell.

Answers

its the chloroplast.thats the part that that makes energy and oxygen in the cell

The answer is chloroplast. It is the organelle in the plant cells that is responsible for photosynthesis, the process that plants use to make oxygen and food.

Plz help.How do ions form electrically neutral compounds?

Answers

They form electrically neutral compounds because the number of captions (positively charged ions) is equal to the number of anions (negativley charged ions) These ions are held together by strong electrostatic forces of attraction.

019 10.0 pointsA ball is thrown horizontally from the top of
a building 120 m high. The ball strikes the
ground 64 m horizontally from the point of
release.
What is the speed of the ball just before it
strikes the ground?
Answer in units of m/s.
020 (ment 1
210,

Answers

Answer:

50.2 m/s

Explanation:

First of all, we need to find the time it takes for the ball to reach the ground.

The vertical position of the ball at time t is given by

$y(t) = h +ut + (1)/(2)gt^2$

where

h = 120 m is the initial height

u = 0 is the initial vertical velocity

g = -9.8 m/s^2 is the acceleration of gravity

The ball reaches the ground when y = 0. Substituting into the equation and solving for t, we find the time of light:

$0=h+(1)/(2)gt^2\nt=\sqrt{-(2h)/(g)}=\sqrt{-(2(120))/(-9.8)}=4.95 s$

The vertical component of the velocity of the ball changes following the equation

$v_y(t) = u+gt$

Substituting t = 4.95 s, we find the final vertical velocity of the ball just before reaching the ground:

$v_y=0+(-9.8)(4.95)=-48.5 m/s$

where the negative sign means the direction is downward.

We also can find the horizontal component of the velocity: since we know the horizontal distance travelled is d = 64 m,

$v_x = (d)/(t)=(64)/(4.95)=12.9 m/s$

And the final speed is calculated as the magnitude of the resultant of the two components of the velocity:

$v=√(v_x^2+v_y^2)=√(12.9^2+(-48.5)^2)=50.2 m/s$

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