Answer:
1.54×10^20 atoms
Explanation:
It'sdonebyusingtherelation
N=n×Lwhere,
N=numberofentitiespresent
n=amountofsubstance (mole)
L=Avogadro'sconstantwhichis6.02×10^23
nowfromthequestion, given
n=0.000256
AndL=6.02×10^23
N=0.000256×6.02×10^23
N=1.54×10^20atoms
Answer:
aka: A
Explanation:
Explanation:
It is known that at STP, there are 22.4 L present in one mole of a substance.
Therefore, in 68.5 liters there will be 1 mol divided by 22.4 L times 68.5 L.
Mathematically,
= 3.05 mol
Hence, we can conclude that there are 3.05 moles present in 68.5 liters of oxygen gas at STP.
Following the ideal gas law PV = nRT, and changing it in terms of temperature, we get T = PV/nR. When volume of a sample of an ideal gas to double when the pressure of the sample remains the same, the temperature doubles because temperature is directly proportional with pressure and volume.
The Answer Is True :) Took The Test:)
b. 3
c. 5
d. 6
It would be: 2*3 = 6 oxygen atoms
OPTION D IS YOUR ANSWER......