Martin is planting a vegetable garden.each row is two meters long.he wants to plant carrots along 3/4 of each row .how many meters of each row will he plant with carrots

Answers

Answer 1

Answer: $2 m * (3)/(4) = (6)/(4) m = (3)/(2) m = 1.5m$

Answer 2

Answer: your answer is 1.5m

Hope this helps.

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Find the area of a trapezoid with bases of 15cm and 6 cm and a height of 1/5cm

Answers

area = 0.5 x (a+b) x h

= 0.5 x (15cm + 6cm) x 1/5cm
= 0.1 x 21cm
=2.1cm^2 (2.1 centimeters squared)

area is 0.5 x h x(a+b)

Juan always saves the same amount from his weekly allowance. The table shows how much he has saved at different times.How much will Juan have saved in 14 wk?

Juan’s Savings

Weeks
3 6 9 12
Amount saved 19 28 37 46

Answers

On the 14 week Juan will save $ 52 because each 3 week he earns 3.
So you do 9 divide by 3 and get 3. Then you do 3 times 2 and get 6.
46 + 6 = 52
~JZ

Expand the following:

Answers

Hey there!

3/4(-24x - 16)

DISTRIBUTE 3/4 WITHIN PARENTHESES

= 3/4(-24x) + 3/4(-16)

= -18x - 12

Therefore, your answer is: -18x - 12

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Gm someone help me ?

Answers

Letter D.

Congruent shapes have the same angles, proportions, etc. but they're not always the same size.

Hope it helped,

Happy homework/ study/ exam!

a is correct since if 2 figures are congruent they have common sides and angles sas postulate and sss postulate

At present Asha's age (in years) is two more than the square of her daughter Nisha's age (in years). When Nisha grows to her mother's present age, Asha's age would be one year less than 10 times the present age of Nisha. Find the present age of Asha and Nisha

Answers

Answer:

Asha's present age is 27 years and Nisha's present age is 5 years.

Step-by-step explanation:

Let the present age of Nisha be $x$ years.

As per question, Asha's present age is 2 more than the square of Nisha's age.

$\therefore$ Asha's present age = $x^2+2$

Now, Nisha will reach her mother's age after $x^2+2-x$ years.

Therefore, age of Asha after $x^2+2-x$ years will be = $x^2+2+x^2+2-x=2x^2-x+4$

Now, as per question,

$2x^2-x+4=10x-1\n2x^2-x-10x+4+1=0\n2x^2-11x+5=0\n2x^2-x-10x+5=0\nx(2x-1)-5(2x-1)=0\n(2x-1)(x-5)=0\nx=(1)/(2)\ or\ x=5$

As age can't be in fraction, we consider the present age of Nisha as 5 years. So, Asha's present age is $x^2+2=5^2+2=25+2=27$ years.

Therefore, Asha's present age is 27 years and Nisha's present age is 5 years.

Rhett made mini waffle cones for a birthday party. Each waffle cone was 3.5 inches high and had a radius of 0.8 inches . what is the volume of each cone to the nearest hundredth?

Answers

v=(1/3)(h)pi(r^2)
h=3.5
r=0.8
v=(1/3)3.5pi0.8^2
v=(1/3)3.5pi0.64
v=1/3pi2.24
v=(2.24/3)pi
aproxpi=3.14
v=(2.24/3)3.14
v=2.34453333333333
hundreth
2.34 in^3

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