A speedy river barge bound for New Orleans, Louisiana leaves Baton Rouge at 9:00 a.m. and travels at a speed of 10 miles per hour. A rail transport freight also bound for New Orleans leaves Baton Rouge at 1:30 p.m. on the same day. The train travels at 25 miles per hour, both the barge and train will travel 100 miles to reach New Orleans. How far will the train travel before catching up to the barge?

Answers

Answer 1
Answer: okay i get it now
1) At 1.30 p.m. the barge has already traveled 4.5 X 10 = 45 miles.

To catch up it will take the train 25-10 = 15miles

Answer 2
Answer:

Answer:

Step-by-step explanation:

A rail transport freight train also bound for New Orleans leaves Baton Rouge at 1;30 PM on the same day. The train travels at 25 MPH and the river barge travels at 10 MPH. ... the barge leaves at 9:00 am so that would be at 9 hours past midnight. the train leaves at 1:30 pm so that would be at 13.5 hours past midnight.


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Answers

Both Diana and Becky ran the same distance with no one running more than the other.

Distance

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Find out more on distance at: brainly.com/question/17273444

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Step-by-step explanation:

HELP ME CHECK MY ANSWER PLEASE!!!

Answers

you have alot of question so I will say if it is right or wrong and explain if  it is wrong

1. correct 10a√a

2.correct 2ab ∛b^2

3. incorrect, answers are 2nd one and fourth one
x^3√(2xy)-4x√(2xy)
(2x^3y-4x)√(2xy)

4. incorrect, answer is 6√3

5.incorrect,  answer is last one 3√6-3√2

6. correct

7. incorrect, if a>b then a/b is not a fraction, that means that is a rational number that is greater than 1 and exponents to numbers greater than 1 get bigger

answer is 3rd and 4th
\sqrt[b]{100^(a) }
expression is greater han 100

8. incorrect, since it is the 3rd root, reverse it and get 3^3=27
answer is 27x^(3/5)


9. incorrect, the answer is 4x^(2/3) because pemdas says that the exponents before multiplication

10. incorrect, answer is use pemdas
ansewr is \frac{9b^{ (3)/(8) }}{a}