PHYSICS HIGH SCHOOL

The distance from one Crest to the next cest is the

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Answer 1
Answer:

Hi


The distance from one Crest to the next crest is the wavelength


I hope that's help !

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Keeping in mind the average reaction time, a motorist will travel 11 feet for each __________ of speed before hitting the brake.

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The answer is for Each 10 MPH

It's usually written in the hand book if you want to take a Driver permit test.

They want us to always maintain a safe distance between vehicles because if somehow we suddenly step on a brake , the other driver cannot instantly stopped on the spot and could potentially cause a crash

If the abosolute of a gas is 600 k, the temperature in degrees Celsius is

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Absolute Zero (Zero Kelvin) = -273.15° Celsius.

Zero° Celsius = 273.15 Kelvin .

600 K  =  (600 - 273.15°) = 326.85°C.

Why is it necessary that the solar concentrators used by solar power plants be able to move throughout the day?

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to track the sun as it moves through out the day
To track the sun as it's moving across the sky. Hope this helps! 

In 2005, the space probe Deep Impact launched a 370 kg projectile into Comet Temple 1. Observing the collision helped scientists learn about the comet’s characteristics. The comet is estimated to have a mass of about 9.0 x 10^13 kg.a. Assuming the estimated mass of the comet at that time was correct, at what distance from the comet’s centre was the gravitational force between the comet and the projectile 32 N?

b. Deep Impact also released a probe to fly by the comet and record images of the collision. Determine the strength of the comet’s gravitational field at the probe’s distance of 5.0 x 103 km from the comet.

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Parta a.

Equation: F = G*m1*m2/d^2

Where
F = 32 N
G = 6.67*10^-11 N.m^2/kg^2
m1 = 9.0*10^13kg
m2 =370 kg
d = distance that separate the center of the two objects.

d^2 = G*m1*m2 / F = 6.67*10^-11 N.m^2/kg^2 * 9.0*10^13 kg *370 kg / 32N = 69,409.69 m^2

d = √69,409.69m^2 = 263.5 m

Part B.

The gravitational field of the comet is g = G*m1/d^2

Notice that it does not depend on the mass of other objects.

Notice also that I will use a distance of 5.0 * 10^3 km, because I think that that is the number that you intended to write in the part b. If that is not the number you can put the right number instead because the solution is written step by step.

g = (6.67*10^-11 N*m^2/kg^2)*(9.0*10^13kg)/(5.0*10^3*10^3m)^2 = 2.4*10^-4 N/kg = 2.4*10^-4 m/s^2

An object, m=1.7 kg, is dropped from a ladder 2 m off the ground. What is the velocity of the object right before its hits the ground?

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v^2 = u^2 + 2as
u=0 m/s
a=g=10 m/s^2
s=2 m

When a river or stream flows downward into a basin that is surrounded by high ground on all sides, what can form?

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When a river or stream flows downward into a basin that is surrounded by high ground on all sides, a waterfall can form. The answer to the question above is 'waterfall' or 'waterfalls'. I hope this helps you on your assignments. You're welcome! 
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