A light rail service claims to be on time 98% of the time.Jeanette takes the light rail 40 times in one month how many times can she predict she will be on time is the light rails claim accurate if she is late 6 times

Answers

Answer 1
Answer:

Answer:

Jeanette would be on time on 85% of her trips.

Step-by-step explanation:

If the light rail service claims to be on time 98% of the time, it should arrive on time at least 39 of 40 times, as 40 x 98 / 100 is equal to 39.2. In consequence, as Jeanette's service arrived late in 6 of over 40 times, we can affirm that what the light rail stated was incorrect. A delayed service in 6 of 40 times has a punctuality rate of 85%, since 6 is the 15% of 40 (40 x 15 / 100 = 40).

Answer 2
Answer: If the claim is accurate she should be on time

98% x 40 =
.98 x 40 = 39.2 times out of 40

If she is late 6 times, the claim is inaccurate.

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Where does the ordered pair (-3, 2) fall in comparison to the line y = x ?

Answers

Answer:

above the line

Step-by-step explanation:

Given the equation y = x

Then the point (- 3, - 3) would lie on the line

and the point (- 3, 2 ) is therefore above the line

Find the other two vertices of a square with one vertex (0, 0) and another vertex (4, 2). Can you find another answer?

Answers

It is given that two vertices of square are (0,0) and (4,2).

Now the problem is that you haven't given that whether these two vertices are adjacent vertices or opposite vertices of the square.

1. By Supposing that these two are adjacent vertices of Square

The third vertex will be at (-4,2) which lies in third quadrant.

Suppose the coordinate of fourth vertex be (x,y).

Mid point of line joining (4,2) and (-4,2) is{ [4+(-4)]/2,(2+2)/2} is (0,2).

Mid point of line joining (x,y) and (0,0) is (x/2,y/2).

Since diagonals of square bisect each other,

∵ x/2=0

⇒x=0

and

y/2=2

⇒y=4

So, The Coordinate of  fourth vertex is (0,4).

Now coming back to second condition if these are two opposite vertex of Square.

Let the third coordinate be (a,b).

Length of diagonal=√((4-0)^2+(2-0)^2)=\sqrt20=2\sqrt5

Now,let side of Square be A.

Then length of Diagonal of square =√2 A

⇒√2 A=2√5

⇒A =√10

As third vertex is (a,b).

Using distance formula

a² + b²=10  -------------(1)

(a-4)²+ (b-2)²=10  --------------(2)

Solving expression (1) and (2), we get

⇒a²+ b²=(a-4)² +(b-2)²

⇒2a + b =5

⇒b=5-2a

Putting the value of b in (1),we get

⇒a² +(5-2a)²=10

⇒a²+25+4a²-20a =10

⇒5a²-20a+15=0

⇒a² - 4a + 3=0

Splitting the middle term,we get

⇒(a-3)(a-1)=0

⇒a=3  ∧  a=1

we get b=5-2×1=3 and b=5-2×3=5-6=-1

So,the other vertex are (1,3) and(3,-1).





The other two vertices of the square are (-4, -2) and (-2, 4).

What are the other two vertices of a square with one vertex (0, 0) and another vertex (4, 2)?

To find the other two vertices of a square with one vertex at (0, 0) and another vertex at (4, 2), you can use the properties of a square, which has equal sides and right angles.

1. First, find the vector from the first vertex (0, 0) to the second vertex (4, 2). This vector represents one side of the square.

  Vector = (4 - 0, 2 - 0) = (4, 2)

2. Since the square has equal sides, you can move in the opposite direction of the vector to find the third vertex.

  Third Vertex = (0, 0) - (4, 2) = (-4, -2)

3. Now, to find the fourth vertex, you can rotate the vector by 90 degrees counterclockwise. To do this, swap the x and y components and negate the new x component:

  Fourth Vertex = (-2, 4)

So, the other two vertices of the square are (-4, -2) and (-2, 4).

Learn more on vertices here;

brainly.com/question/1217219

#SPJ4

What is f + 0.3 < 1.7 I need help solving this please can anybody help me I Tryed and I can't get the answer ?? ??? ??

Answers

f + 0.3 < 1.7

f < 1.7 - 0.3

f < 1.4

hope this helps!!

Subtract 0.3 from each side.

f<1.4
is what you will get.

What is the weight of a car

Answers

It matters what type of car it is. It could weigh about 3000 to like 6000

PLEASE HELP I GIVE THANKS

Answers

Let's plug the given value is in the formula : { V }_( cylinder )=\quad \pi { r }^( 2 )h 

First cylinder : { V }_( cylinder1 )=\quad \pi { 8 }^( 2 )21=\pi \cdot 64\cdot 21=1344\pi \quad { cm }^( 3 )

Second cylinder : { V }_( cylinder2 )=\quad \pi { 11 }^( 2 )45=\pi \cdot 121\cdot 45=5445\pi \quad { cm }^( 3 )

5445-1344=4101\n \n 4101\pi \quad { cm }^( 3 )

Answer is D

Is this proportional

Answers

Answer:

yes

Step-by-step explanation:

its a straight line

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