106 over 500 as a decimal number

Answers

Answer 1

Answer: 106/500 as a decimal is: 0.212.

You can easily find the decimal of a fraction by doing long division or inserting the fraction in a calculator (which teachers usually allow their students to use a calculator even on tests... unless if the test is about long division, etc).

Long division is pretty hard to do without a pen and paper, but the steps to do long division are: divide the number on the right by the left number - multiply the number on the left by the top number - subtract the number on the right by the number below it - bring down, and then repeat if you can.

Answer 2

Answer: $(106)/(500)$
0.212

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Find the surface area of the cylinder in terms of .

Answers

The surface area of the cylinder= 2 π * r^2

Step-by-step explanation:

The surface area of each end and the surface area of the side of the cylinder are added to get surface area of a cylinder.

We know that each end of the cylinder is a circle.

So the surface area of each end of the cylinder is π * r^2

Here, r is the radius of the end

There are two ends, so their combined surface area= 2 π * r^2

The surface area of the cylinder= 2 π * r^2

Multiply the binomials (3x - 5) and (4x + 6).

Answers

Answer:

12x² - 2x - 30

Step-by-step explanation:

When multiplying binomials, remember to follow the FOIL method:

FOIL =

First

Outside

Inside

Last

Follow FOIL: (3x - 5)(4x + 6)

(3x)(4x) = 12x²

(3x)(6) = 18x

(-5)(4x) = -20x

(-5)(6) = -30

Combine like terms, simplify:

12x² + 18x - 20x - 30

12x² + (18x - 20x) - 30

12x² - 2x - 30

12x² - 2x - 30 is your answer.

Answer:

12x²-2x-30=2(6x²-x-15)

Step-by-step explanation:

(3x-5)(4x+6)=12x²-20x+18x-30=

12x²-2x-30=2(6x²-x-15)

A rectangular shape is shown with the numbers 5 and 10 what is thw area

Answers

50 is the answer 5×10 50 is the area

Area= L* W
⇒ Area= 10*5= 50

The area of the rectangular shape is 50~

Write an equation in slope intercept form of the line m=3/2 and contains the point 2,9

Answers

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{9})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{3}{2} \n\n\n \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\n \cline{1-1} \n y-y_1=m(x-x_1) \n\n \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{2}) \n\n\n y-9=\cfrac{3}{2}x-3\implies y=\cfrac{3}{2}x+6$