The range of the data set {33.4, 31.7 ,31.3, 35.6, 33.4, 33.5, 38.8, 39.2, 38.8, 33.4, 37.8} is R = 7.9
Given details in the problem :
The data set : 33.4, 31.7 ,31.3, 35.6, 33.4, 33.5, 38.8, 39.2, 38.8, 33.4, 37.8
In statistics, The range is the spread of your data from the lowest to the highest value in the distribution. It is a commonly used measure of variability.
The range is calculated by subtracting the lowest value from the highest value. While a large range means high variability, a small range means low variability in a distribution.
Rearrange the given Data Set : 31.3, , 31.7 , 33.4, 33.4, 33.4, 33.5, 35.6, , 37.8 , 38.8, 38.8, 39.2,
The lowest Value of the data set is 31.3
The Highest value of the data set is 39.2
The formula to calculate the range is:
R =H- L
R = range
H = highest value
L = lowest value
R = 39.2-31.3
R = 7.9
The range of the data set {33.4, 31.7 ,31.3, 35.6, 33.4, 33.5, 38.8, 39.2, 38.8, 33.4, 37.8} is R = 7.9
Learn more about Data Set: brainly.com/question/22210584
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Answer:
- 0.3
Step-by-step explanation:
Answer:
(2·4)² = 64 / (6*2)² = 144
Step-by-step explanation:
Follow PEMDAS :
Parenthesis first, so:
2 * 4
==> 8
Then Exponent:
8 ^2
==> 64
(2·4)² = 64
Do the same for (6:2)² :
Parenthesis first :
6 * 2
==> 12
Then Exponent:
12^2
==> 144
(6:2)² = 144
Answer:
Step-by-step explanation:
First, multiply the numbers inside the parenthesis. So
1. 2*4 = 8
2. 6*2 = 12
Next, Use the exponents
1. 8^2
2. 12^2
Finally, solve using exponents.
1. 8^2 = 64
2. 12^2 = 144
So 64 and 144 is the answer.
Hope this helped,
Kavitha
Which value is changed the most by removing the outlier?
A: the range
B: the median
C: the lower quartile
D: the interquartile range